Question

我已将文件上传到MySQL数据库，但在检索时我遇到了问题。

的download.php

<?php

    $host="localhost";
                $username="root";
                $password="";
$db_name="application";

$con=mysqli_connect("$host", "$username", "$password","$db_name")or die("Your Connection is in error");

$a =$_GET['contactid'];

$query = "SELECT filename,filetype,filesize,filecontent FROM contact WHERE contactid = '$a' ";

$result = mysqli_query($con,$query) or die('Error, query failed');
list($filename, $filetype, $filesize, $filecontent) = mysqli_fetch_array($result);

header("Content-length: $filesize");
header("Content-type: $filetype");
header("Content-Disposition: attachment; filename=$filename");
echo $filecontent;
exit;
?>

我从上一个屏幕获得的$ a无效。相反，如果我给contactid = 18 ..文件正在下载。

上一个screen.php

$GET =mysqli_fetch_array(mysqli_query($con,"SELECT contactid,groupname,firstname,lastname,mobile1,mobile2,email1,email2,city,country,designation,companyname,address1,address2,district,pincode,website,others,filename FROM contact WHERE contactid='$a'"));
$contactid   = $GET['contactid'];
$filename  = $GET['filename'];
<a href='download.php?contactid=".$contactid."'><?php echo $filename;?>    </a>

Answer 1

<a href='download.php?contactid=".$contactid."'><?php echo $filename;?>    </a>

使用两个php变量$contactid和$filename的上述语句。您有echo $filename但忘了回复$contactid。如果上述陈述不在PHP标签内。那应该是，

<a href='download.php?contactid=<?php echo $contactid ?>'><?php echo $filename;?>    </a>

如果它在PHP标签内，则应该是，

echo "<a href='download.php?contactid=".$contactid."'>".$filename."</a>";

Answer 2

使用

 "...... where contactid='".$a."'";

从mysql数据库下载文档

2 个答案: