Question

String Res[][]={{"af","ea","ff","ea"},  
{"ea","ba","cc","aa"},
{"aa","cb","bc","cc"},
{"0a","ad","da","ff"}};

我正在实现AES 128位密钥。而解密我得到4乘4矩阵的十六进制值。如何将其转换为字符串？

Answer 1

如果你想要这样的东西“afeaffeaeabaccaaaacbbccc0aaddaff”，那就是：

    String Res[][]={{"af","ea","ff","ea"},  
    {"ea","ba","cc","aa"},
    {"aa","cb","bc","cc"},
    {"0a","ad","da","ff"}};
    StringBuilder strBldr = new StringBuilder();
    for(String[] ar : Res) {
        for(String str : ar) {
            strBldr.append(str);
        }
    }
    System.out.println(strBldr.toString());

http://ideone.com/2jfMob

如果您打算将其转换为字符，可以在循环中替换：

strBldr.append((char) Integer.parseInt(str, 16));

假设字符由一个字节表示。如果没有，请参阅前。这个：http://ideone.com/kg2ZN5

如何将4乘十六进制值的4矩阵转换为明文？

1 个答案: