Question

我有一个像这样结构化的SQLite数据库：

ID      Date              Time           Cost
"1" "2016-05-14"    "17:39:35.925973"   "1.98"
"2" "2016-05-14"    "17:39:54.181083"   "2.84"
"3" "2016-05-14"    "17:40:26.408492"   "2.99"
"4" "2016-05-14"    "17:41:28.197353"   "3.39"
"25"    "2016-05-19"    "14:44:27.235790"   "2.5"
"26"    "2016-05-19"    "14:46:35.177696"   "1.58"
"27"    "2016-05-19"    "14:49:12.902651"   "0.1"   
"28"    "2016-05-20"    "21:35:32.446997"   "2.25"

我想在一个月和一年中总结成本，无视当天。

我在python中这样做，但我甚至不知道sqlite代码只选择月份和年份。

我试过这段代码：

def SumByMonth():
    usrDate = raw_input('Enter yymm: ')
    dateyear = datetime.datetime.strptime(usrDate, "%y%m").date()
    month_sql = '''SELECT cost FROM Finance WHERE strftime('%m%y', date) = ( ?  )'''
    month_price = [t[0] for t in cur.execute(month_sql, ( dateyear,) )]
    sum_total = sum(month_price)
    print 'sum is for', dateyear,'is', sum_total

所有我回来的都是sum is for 2016-05-01 is 0所以它似乎是在没有提供一天的情况下选择该月的第一天。我怎样才能选择月份和年份？

由于

Answer 1

SQLite没有2位数年份的格式说明符。参考：https://www.sqlite.org/lang_datefunc.html

而且，正如@DanielRoseman所提到的那样：

你混淆了你的岁月，
您不必要地将字符串转换为日期时间。

取而代之的是：

def SumByMonth():
    yyyymm = raw_input('Enter yyyymm: ')
    month_sql = '''SELECT cost FROM Finance WHERE strftime('%Y%m',date) = ?'''
    month_price = [t[0] for t in cur.execute(month_sql,(yyyymm,))]
    sum_total = sum(month_price)
    print 'sum is for', yyyymm,'is', sum_total

你可以做得更精彩：

def SumByMonth():
    yyyymm = raw_input('Enter yyyymm: ')
    month_sql = '''SELECT SUM(cost) FROM Finance WHERE strftime('%Y%m',date) = ?'''
    sum_total = cur.execute(month_sql,(yyyymm,)).fetchone()[0]
    print 'sum is for', yyyymm,'is', sum_total

仅选择日期和年份SQLite

1 个答案: