Question

我想要一个列显示每个类别的总和（AMOUNT）（超过90，超过60，超过30）

DECLARE @DATE VARCHAR(10)
SET @DATE='2012-12-31' 
SELECT TRANDATE, TRANTYPE, INVNUM,SUM (AMOUNT), PAID, CLIENTID, 

      (CASE  WHEN TRANDATE <= DATEADD(dd, -90, @DATE) THEN  SUM(AMOUNT) END ) AS 'OVER 90', 
      (CASE  WHEN TRANDATE<DATEADD(dd, -90, @DATE) AND  TRANDATE<=DATEADD(dd, -60, @DATE) THEN SUM(AMOUNT) END) AS 'OVER 60' ,  
      (CASE  WHEN TRANDATE<DATEADD(dd, -60, @DATE) AND  TRANDATE<=DATEADD(dd, -30, @DATE) THEN SUM(AMOUNT) END)AS  'OVER 30' ,
      (CASE  WHEN TRANDATE<DATEADD(dd, -30, @DATE) THEN SUM(AMOUNT) END) AS 'CURRENT'            
from Bill
where  TRANTYPE IN ('INV', 'PAY') AND   TRANDATE<=@DATE AND CLIENTID=7434
GROUP BY TRANDATE, TRANTYPE, INVNUM, PAID, CLIENTID

我该怎么办？我试过但没有真正的价值。谢谢你的评论和回答。

TRANDATE    TRANTYPE   INVNUM  AMOUNT  PAID    CLIENTID  OVER90  OVER60  OVER30
2012-05-06   INV       230496  7803.50 7803.50  7434     7803.50  NULL   NULL

Answer 1

试试这个......

DECLARE @DATE VARCHAR(10)
SET @DATE='2012-12-31' 
SELECT TRANDATE, TRANTYPE, INVNUM,SUM (AMOUNT), PAID, CLIENTID, 

      SUM((CASE  WHEN TRANDATE <= DATEADD(dd, -90, @DATE) THEN  AMOUNT END )) AS 'OVER 90', 
      SUM((CASE  WHEN TRANDATE>DATEADD(dd, -90, @DATE) AND  TRANDATE<=DATEADD(dd, -60, @DATE) THEN AMOUNT END)) AS 'OVER 60' ,  
      SUM((CASE  WHEN TRANDATE>DATEADD(dd, -60, @DATE) AND  TRANDATE<=DATEADD(dd, -30, @DATE) THEN AMOUNT END))AS  'OVER 30' ,
      SUM((CASE  WHEN TRANDATE>DATEADD(dd, -30, @DATE) THEN AMOUNT END)) AS 'CURRENT'            
from Bill
where  TRANTYPE IN ('INV', 'PAY') AND   TRANDATE<=@DATE AND CLIENTID=7434
GROUP BY TRANDATE, TRANTYPE, INVNUM, PAID, CLIENTID

在'CURRENT'的代码条件中，'Over 30'和'Over 60'正在检查TRANDATE＆lt;这应该是TRANDATE＆gt;

Answer 2

将案例陈述包裹在SUM：

中

DECLARE @DATE VARCHAR(10)
SET @DATE='2012-12-31' 
SELECT TRANDATE, TRANTYPE, INVNUM,SUM (AMOUNT), PAID, CLIENTID, 
      SUM(CASE  WHEN TRANDATE <= DATEADD(dd, -90, @DATE) THEN  AMOUNT END ) AS 'OVER 90', 
      SUM(CASE  WHEN TRANDATE<DATEADD(dd, -90, @DATE) AND  TRANDATE<=DATEADD(dd, -60, @DATE) THEN AMOUNT END) AS 'OVER 60' ,  
      SUM(CASE  WHEN TRANDATE<DATEADD(dd, -60, @DATE) AND  TRANDATE<=DATEADD(dd, -30, @DATE) THEN AMOUNT END) AS  'OVER 30' ,
      SUM(CASE  WHEN TRANDATE<DATEADD(dd, -30, @DATE) THEN AMOUNT END) AS 'CURRENT'            
from Bill
where  TRANTYPE IN ('INV', 'PAY') AND   TRANDATE<=@DATE AND CLIENTID=7434
GROUP BY TRANDATE, TRANTYPE, INVNUM, PAID, CLIENTID

Answer 3

编写一个不对CASE语句进行分组的查询，以获取值为

的计算列

＆＃39;超过90＆＃39;，＆＃39;超过60＆＃39;超过30＆＃39;超过30＆＃39;在它根据记录，名称列任何东西，例如MySection

然后查询并将此查询分组为一个来源的查询 - 包装您的子查询，将您的所有字段以及年龄放入主查询中

，例如

    SELECT TRANDATE, TRANTYPE, INVNUM,MySection,SUM (AMOUNT), PAID, CLIENTID, 

from ( ... your derived query in here..) AS DQ
where  TRANTYPE IN ('INV', 'PAY') AND   TRANDATE<=@DATE AND CLIENTID=7434
GROUP BY TRANDATE, TRANTYPE, INVNUM, PAID, CLIENTID, MySection

显示每个类别的sum（）的列

3 个答案: