Question

所以我有这张桌子;

的MySQL＆GT;描述player_weapon_stats;

+------------+------------------+------+-----+---------+----------------+
| Field      | Type             | Null | Key | Default | Extra          |
+------------+------------------+------+-----+---------+----------------+
| id         | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| players_id | int(10) unsigned | NO   |     | NULL    |                |
| weapons_id | int(10) unsigned | NO   |     | NULL    |                |
| matches_id | int(10) unsigned | NO   |     | NULL    |                |
| hits       | int(10) unsigned | NO   |     | NULL    |                |
| shots      | int(10) unsigned | NO   |     | NULL    |                |
| kills      | int(10) unsigned | NO   |     | NULL    |                |
| acc        | decimal(4,2)     | NO   |     | NULL    |                |
+------------+------------------+------+-----+---------+----------------+
8 rows in set (0.00 sec)

有很多行（目前大约400k），像这样;

的MySQL＆GT; select * from player_weapon_stats ORDER BY id ASC LIMIT 5;

+----+------------+------------+------------+------+-------+-------+-------+
| id | players_id | weapons_id | matches_id | hits | shots | kills | acc   |
+----+------------+------------+------------+------+-------+-------+-------+
|  1 |          1 |          1 |          1 |    5 |     0 |     1 |  0.00 |
|  2 |          1 |          2 |          1 |  133 |   437 |     2 | 30.43 |
|  3 |          1 |          3 |          1 |  247 |   896 |     8 | 27.57 |
|  4 |          1 |          4 |          1 |    0 |    11 |     0 |  0.00 |
|  5 |          1 |          5 |          1 |   35 |    59 |     9 | 59.32 |
+----+------------+------------+------------+------+-------+-------+-------+
5 rows in set (0.02 sec)

所以每场比赛每位玩家的武器统计数据会被记录

我想要做的是根据每个玩家的总和来获得每个weapon_id的最高acc

返回的行数应与武器数量相等（在本例中为8）

这是我试过的;

mysql> SELECT players_id, weapons_id, SUM(hits) AS hits, SUM(shots) AS shots, SUM(kills) AS kills, (FORMAT(hits / shots, 4) * 100) AS acc FROM player_weapon_stats GROUP BY weapons_id ORDER BY acc DESC;
// no player association so SUM totals up all players together

mysql> SELECT players_id, weapons_id, SUM(hits) AS hits, SUM(shots) AS shots, SUM(kills) AS kills, (FORMAT(hits / shots, 4) * 100) AS acc FROM player_weapon_stats GROUP BY weapons_id, players_id ORDER BY acc DESC, weapons_id ASC LIMIT 10;
// incorrect acc and around 25k rows returned

mysql> SELECT players_id, weapons_id, SUM(hits) AS hits, SUM(shots) AS shots, SUM(kills) AS kills, (FORMAT(hits / shots, 4) * 100) AS acc FROM player_weapon_stats GROUP BY players_id, weapons_id ORDER BY acc DESC, weapons_id ASC;
// appears correct acc, and correct totals but returns around 25k rows as well

我已经尝试了很多以上的变化以及当时想到的任何其他东西，但我仍然卡住了...我想我一直盯着它看太久了

任何人都可以帮助我吗？

----编辑

我使用的样本数据有点太小而无法编译成结果，因为每个players_id的每个weapon_id会有多个条目，然后将这些条目加在一起形成该玩家/武器的“平均/整体”; < / p>

http://pastebin.com/Q1N5mScU

当你看到4个玩家的每个武器的累加总数时......所以预期的结果将类似于那个，但每个武器只需一行

我不确定如何解释它

----第二次编辑

mysql> SELECT players_id, weapons_id, MAX(acc) FROM (SELECT weapons_id, players_id, AVG(acc) AS acc FROM player_weapon_stats GROUP BY players_id, weapons_id) AS t1 GROUP BY weapons_id;
    +------------+------------+-----------+
    | players_id | weapons_id | MAX(acc)  |
    +------------+------------+-----------+
    |          1 |          0 | 25.000000 |
    |          1 |          1 |  0.000000 |
    |          1 |          2 | 84.995000 |
    |          1 |          3 | 99.990000 |
    |          1 |          4 | 99.990000 |
    |          1 |          5 | 94.290000 |
    |          1 |          6 | 70.250000 |
    |          1 |          7 | 99.990000 |
    |          1 |          8 | 99.990000 |
    +------------+------------+-----------+
    9 rows in set (0.33 sec)

----第3次编辑

似乎是基于jcrummacks查询的解决方案;

mysql> SELECT players_id, weapons_id, hits, shots, kills, MAX(acc) FROM ( SELECT players_id, weapons_id, SUM(hits) AS hits, SUM(shots) AS shots, SUM(kills) AS kills, AVG(acc) AS acc FROM player_weapon_stats GROUP BY players_id, weapons_id ORDER BY weapons_id ASC, AVG(acc) DESC) AS t1 GROUP BY weapons_id;
+------------+------------+------+-------+-------+-----------+
| players_id | weapons_id | hits | shots | kills | MAX(acc)  |
+------------+------------+------+-------+-------+-----------+
|        202 |          0 |    1 |     3 |     0 | 25.000000 |
|       1544 |          1 |    1 |     0 |     0 |  0.000000 |
|       3034 |          2 |    8 |    11 |     0 | 84.995000 |
|        952 |          3 |   16 |    16 |     0 | 99.990000 |
|       3493 |          4 |    1 |     1 |     0 | 99.990000 |
|        839 |          5 |   33 |    35 |     2 | 94.290000 |
|        734 |          6 |  366 |   521 |     5 | 70.250000 |
|       2643 |          7 |    1 |     1 |     0 | 99.990000 |
|       3227 |          8 |    1 |     1 |     0 | 99.990000 |
+------------+------------+------+-------+-------+-----------+
9 rows in set (0.72 sec)

Answer 1

我在这里阅读我认为你想要的内容，并假设你在一个相当新的版本的mysql（需要派生表支持），即使我不是你想要的可能这将指出你正确的方向。

select
  players_id,
  weapons_id,
  max(acc)
from (
  select
    weapons_id,
    players_id,
    avg (acc) as acc
  from
    player_weapon_stats
  group by
    players_id,
    weapons_id
  order by 
    weapons_id asc, 
    avg(acc) desc) as t1
group by 
  weapons_id

希望我朝着你想去的方向前进。

Answer 2

听起来好像你想要每个武器一排，任何玩家都可以达到最高精度。如果是这样，请尝试以下操作：

SELECT weapons_id, 
       SUM(hits) AS hits, 
       SUM(shots) AS shots, 
       SUM(kills) AS kills, 
       MAX(acc) AS acc 
FROM (SELECT players_id, 
             weapons_id, 
             SUM(hits) AS hits, 
             SUM(shots) AS shots, 
             SUM(kills) AS kills, 
             FORMAT(SUM(hits) / SUM(shots), 4) * 100 AS acc 
      FROM player_weapon_stats 
      GROUP BY players_id, weapons_id) SQ
GROUP BY weapons_id

mysql组混乱

2 个答案: