Question

在我的视图页面中，我有一个表格格式的复选框项目列表。当用户单击我的控制器的添加按钮时，我想发送所选复选框的ID（可能是多个id）。在控制器中，我将获取一些值并将其传递给另一个视图。下面是我的代码

<div id="content">
    <div class="container">
        <div class="row">
            <div class="col-md-8">
                <div class="contact_form_holder">
                    {{ Form::open(array('url' => 'booking','METHOD' => 'POST')) }}
                    <div class="col-md-4">
                        {{form::text('checkin','',['class' => 'form-control','placeholder'=>'Check In Date','id'=>'checkin'])}}
                        <div id="error_datepicker" class="error">Please check again</div>
                    </div>
                    <div class="col-md-4">
                        {{form::text('checkout','',['class' => 'form-control','placeholder'=>'Check Out Date','id'=>'checkout'])}}
                        <div id="error_datepicker" class="error">Please check again</div>
                    </div>
                    <p id="btnsubmit">
                        <input type="submit" id="send" value="Search" class="btn btn-custom"/>
                    </p>
                    {{ Form::close() }}
                </div>
                <div class="col-md-12">
                    @if (isset($roomname))
                    <table class="table table-hover" data-toggle="table" id="table"
                           data-click-to-select="true">
                        <thead>
                        <tr>
                            <th data-field="state" data-checkbox="true"></th>

                            <th data-field="roomname">Room Name</th>
                            <th data-field="Desc">Description</th>
                            <th data-field="price">Price</th>
                            <th data-field="roomid" data-visible="false">Price</th>
                        </tr>
                        </thead>
                        <tbody>
                        @foreach($roomname as $value)
                        <tr>
                            <td>{!! $value->roomid !!}</td>
                            <td>{!! $value->roomname !!}</td>
                            <td>{!! $value->Desc !!}</td>
                            <td>{!! $value->price !!}</td>
                            <td>{!! $value->roomid !!}</td>
                        </tr>
                        @endforeach
                        </tbody>
                    </table>
                    @endif
                </div>
                <div class="col-md-12">
                    <br>

                    <button id="add_cart" class="btn btn-warning">Proceed to booking</a></button>
                    <!-- on click of this button i want the clicked item id from the table and send it to the controller and from the controller it shoud redirect the value to another page  -->
                </div>
            </div>

我的javascript

$.ajax({
    url: '/roombooking',
    type: "get",
    data: {id: data},
    success: function (response) { // What to do if we succeed
        if (data == "success") {
        }
    },
    error: function (response) {
        alert('Error' + response);
    }
});

Answer 1

你可以将表包装在form标签中，然后使用jquery serialize（）方法获取ex的所有内容。

   @if (isset($roomname))
          <form id="testForm">
                <table class="table table-hover" data-toggle="table" id="table"
                       data-click-to-select="true">
                    <thead>
                    <tr>
                        <th data-field="state" data-checkbox="true"></th>

                        <th data-field="roomname">Room Name</th>
                        <th data-field="Desc">Description</th>
                        <th data-field="price">Price</th>
                        <th data-field="roomid" data-visible="false">Price</th>
                    </tr>
                    </thead>
                    <tbody>
                    @foreach($roomname as $value)
                    <tr>
                        <td>{!! $value->roomid !!}</td>
                        <td>{!! $value->roomname !!}</td>
                        <td>{!! $value->Desc !!}</td>
                        <td>{!! $value->price !!}</td>
                        <td>{!! $value->roomid !!}</td>
                    </tr>
                    @endforeach
                    </tbody>
                </table>
              </form>
                @endif

然后在javascript使用下面

$.ajax({
    url: '/roombooking',
    type: "get",
    data: $('#testForm').serialize(),
    success: function (response) { // What to do if we succeed
        if (data == "success") {
        }
    },
    error: function (response) {
        alert('Error' + response);
    }
});

确保复选框是html中的数组因此在所有复选框名称属性应该类似

<input type="checkbox" name="selected[]" />

然后在你的laravel控制器中你会得到Request :: all（）将有'selected'数组

Answer 2

要从复选框传递多个ID，您可以通过数组的帮助来完成。假设（例如）如果表单标签中包含的页面上有4个复选框，则可以实现方式 - 代码如下：

<form action="some_url" method="POST">
    <input type="checkbox" name="ids[]" value="1"> My Value 1
    <br />
    <input type="checkbox" name="ids[]" value="2"> My Value 2
    <br />
    <input type="checkbox" name="ids[]" value="3"> My Value 3
    <br />
    <input type="checkbox" name="ids[]" value="4"> My Value 4
    <br />
    <input type="submit" value="Submit">
</form>

因此，如果您通过选中所有复选框提交此表单，则发布数据的输出将如下：

<?php

    $inputs = request()->all();
    /*

     Inputs will have -
     $inputs = array(
        'ids' => array(1, 2, 3, 4);
     );

    */

?>

因此，您将使用Laravel的request()->all()方法接收ID。希望这能帮助您解决问题...... !!

将多个id从复选框传递到Laravel中的控制器

2 个答案: