Question

我正在抓取一个网站获取一些数据，这是一段时间的工作，所以我用Google搜索并发现Queue对这个过程有好处我被困在这个错误中

Serialization of 'Closure' is not allowed

我的代码：

class SiteScraper extends Job implements ShouldQueue
{
    use InteractsWithQueue, SerializesModels;

    protected $client;
    protected $crawler;

    /**
     * Create a new job instance.
     *
     * @return void
     */
    public function __construct()
    {

        $this->client = new Client();
        $this->crawler = $this->client->request('GET', 'example.com/login/');
        $form = $this->crawler->selectButton('Log In')->form();
        $this->crawler = $this->client->submit($form, array('email' => 'useremail', 'pass' => 'pass'));
        $this->crawler->filter('.flash-error')->each(function ($node) {
            print $node->text() . "\n";
        });
    }
 public function handle()
{

    $crawler = $this->client->request('GET', $url_to_traverse);
    $status_code = $this->client->getResponse()->getStatus();

        if($status_code == 200){
            $crawler->filter('.friendBrowserNameTitle > a')->each(function ($node) {
                $names = $node->text() . '<br>';
                $profileurl = $node->attr('href') . '<br>';
                echo "Name : " . $names . "  Profile Link : " . $profileurl;

            });
        }
        else{
            echo $status_code;
        }

    }
}

我出错的任何帮助？

Answer 1

在处理作业时，只有Eloquent模型才会被优雅地序列化和反序列化（Source）

所以我想在你的情况下，你必须将你当前的构造代码写入 handle（）方法

class SiteScraper extends Job implements ShouldQueue
{
    use InteractsWithQueue, SerializesModels;

    /**
     * Create a new job instance.
     *
     * @return void
     */
    public function __construct(){ }

    public function handle()
    {

        $client = new Client();
        $crawler = $client->request('GET', 'example.com/login/');
        $form = $crawler->selectButton('Log In')->form();
        $crawler = $client->submit($form, array('email' => 'useremail', 'pass' => 'pass'));
        $crawler->filter('.flash-error')->each(function ($node) {
            print $node->text() . "\n";
        });

        $crawler = $client->request('GET', $url_to_traverse);
        $status_code = $client->getResponse()->getStatus();

        if($status_code == 200){
            $crawler->filter('.friendBrowserNameTitle > a')->each(function ($node) {
                $names = $node->text() . '<br>';
                $profileurl = $node->attr('href') . '<br>';
                echo "Name : " . $names . "  Profile Link : " . $profileurl;

            });
        }
        else{
            echo $status_code;
        }

    }
}

序列化＆＃39;关闭＆＃39;不允许laravel队列

1 个答案: