我没有看到这个程序有任何错误,任何人都可以解释这个!
<?php
if(isset($_POST['submit'])){
if(isset($_FILES['image_up']['tmp_name']))$image = $_FILES['image_up']['tmp_name'];
if(isset($_FILES['image_up']['name']))$imageName = $_FILES['image_up']['name'];
$image = addslashes($image);
$imageName = addslashes($imageName);
$image = file_get_contents($image);
$image = base64_encode($image);
$upload=uploadimage($image, $imageName);
function uploadimage($image,$imageName){
//Connect to DB
$link = mysqli_connect('localhost','root','');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if(!$selectdb)echo "Something Went wrong_DB try again later";
$query = "insert into upload_image(name,Image)values('$imageName','$image')";
$result = mysqli_query($link, $query);
if(!$result) echo"Error Uploading";
else echo"Uploaded Successfully";
}
displayImage();
}
else echo"Select a File to Upload";
function displayImage(){
$link = mysqli_connect('localhost','root','');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if(!$selectdb)echo "Something Went wrong_DB try again later";
$query = "selct * from upload_image";
$result = mysqli_query($link, $query);
$row = mysqli_fetch_array($result);
echo '<img width="300" height="300" src=data:Image;base64,'.$row[3].'>';
}
?>
我收到致命错误: -
未定义的函数uploadimage()
任何人都可以解释一下吗???
这是我在数据库中创建的表的布局
图像 ID 名称
答案 0 :(得分:0)
将函数移出if(isset($_POST['submit'])){
语句。
<?php
if(isset($_POST['submit'])){
if(isset($_FILES['image_up']['tmp_name']))$image = $_FILES['image_up']['tmp_name'];
if(isset($_FILES['image_up']['name']))$imageName = $_FILES['image_up']['name'];
$image = addslashes($image);
$imageName = addslashes($imageName);
$image = file_get_contents($image);
$image = base64_encode($image);
$upload=uploadimage($image, $imageName);
displayImage();
}
echo "Select a File to Upload";
function displayImage(){
$link = mysqli_connect('localhost','root','');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if(!$selectdb)echo "Something Went wrong_DB try again later";
$query = "selct * from upload_image";
$result = mysqli_query($link, $query);
$row = mysqli_fetch_array($result);
echo '<img width="300" height="300" src=data:Image;base64,'.$row[3].'>';
}
function uploadimage($image,$imageName){
//Connect to DB
$link = mysqli_connect('localhost','root','');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if(!$selectdb)echo "Something Went wrong_DB try again later";
$query = "insert into upload_image(name,Image)values('$imageName','$image')";
$result = mysqli_query($link, $query);
if(!$result)
echo"Error Uploading";
else
echo "Uploaded Successfully";
}
?>
答案 1 :(得分:0)
您需要在任何if else条件之外的页面底部定义所有函数。这是修改后的代码:
<?php
if (isset($_POST['submit'])) {
if (isset($_FILES['image_up']['tmp_name']))
$image = $_FILES['image_up']['tmp_name'];
if (isset($_FILES['image_up']['name']))
$imageName = $_FILES['image_up']['name'];
$image = addslashes($image);
$imageName = addslashes($imageName);
$image = file_get_contents($image);
$image = base64_encode($image);
$upload = uploadimage($image, $imageName);
displayImage();
}
else
{
echo "Select a File to Upload";
}
function uploadimage($image, $imageName) {
//Connect to DB
$link = mysqli_connect('localhost', 'root', '');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if (!$selectdb)
echo "Something Went wrong_DB try again later";
$query = "insert into upload_image(name,Image)values('$imageName','$image')";
$result = mysqli_query($link, $query);
if (!$result)
echo "Error Uploading";
else
echo "Uploaded Successfully";
}
function displayImage() {
$link = mysqli_connect('localhost', 'root', '');
$selectdb = mysqli_select_db($connect2db, 'test_one');
if (!$selectdb)
echo "Something Went wrong_DB try again later";
$query = "selct * from upload_image";
$result = mysqli_query($link, $query);
$row = mysqli_fetch_array($result);
echo '<img width="300" height="300" src=data:Image;base64,' . $row[3] . '>';
}
?>
答案 2 :(得分:0)
你想要在声明之前调用uploadimage函数
$upload=uploadimage($image, $imageName);
function uploadimage($image,$imageName){
在任何php逻辑代码之前移动函数声明