为什么add函数在c ++ 11 thread中没有效果?

时间:2016-06-24 04:30:14

标签: c++ multithreading c++11 output stdthread

我正在尝试学习c ++ 11线程并拥有以下代码:

#include <iostream>
#include <thread>
#include <vector>
#include <mutex>
#include <algorithm>

void add(int&  i){
    std::mutex some_mutex;
   // std::cout << " I am " << std::endl;
    std::lock_guard<std::mutex> guard(some_mutex); 
    i++;
}


int main(){
    int i = 0;
    std::vector<std::thread> vec_threads;

    for(int i = 0; i < 10; i++){
        vec_threads.push_back(std::thread(add,std::ref(i)));
    }

    std::for_each(vec_threads.begin(),vec_threads.end(),
            std::mem_fn(&std::thread::join));
    std::cout<< " i = " << i << std::endl;
return 0;
}

我创建了一个vector,其中包含std::thread,我从每个线程调用add函数并通过ref传递i。在假设线程会做的事情之后(添加i = i+1),最终结果并不反映我想要的。

  

输出:i = 0

     

预期产出:i = 10

1 个答案:

答案 0 :(得分:28)

需要在线程之间共享互斥锁以获得正确的结果。并且i被循环变量遮蔽,请将其替换为j

#include <iostream>
#include <thread>
#include <vector>
#include <mutex>
#include <algorithm>

void add(int&  i, std::mutex &some_mutex){
   // std::cout << " I am " << std::endl;
    std::lock_guard<std::mutex> guard(some_mutex); 
    i++;
}


int main(){
    int i = 0;
    std::vector<std::thread> vec_threads;
    std::mutex some_mutex;

    for(int j = 0; j < 10; j++){
        vec_threads.push_back(std::thread(add,std::ref(i), std::ref(some_mutex)));
    }

    std::for_each(vec_threads.begin(),vec_threads.end(),
            std::mem_fn(&std::thread::join));
    std::cout<< " i = " << i << std::endl;
    return 0;
}