Question

对于类，我需要编写一个从.txt文件获取输入的程序，使用c_strings将其转换为pig latin，然后将结果输出到另一个.txt文件。我已经测试了我自己的每个函数，并使用for（）循环来迭代大约40个函数调用。当我通过大约60次调用但是我的调试断言失败了！ popup陈述

“文件：minkernel \ crts \ ucrt \ inc \ corect_internal_string_templates.h

行：50

表达式：（L“缓冲区太小”＆amp;＆amp; 0）“

这是我对函数的调用。

while(!inputFile.eof())
  {
     engStr = readDataFromFile(inputFile);
     pLatinStr = convertToPigLatin(engStr, pLatinStr);
     outPutResults(outputFile, engStr, pLatinStr);
  }

以下是被调用的函数。

    char * readDataFromFile(ifstream &inFile)
{
   char * arr = new char[20];

   inFile.getline(arr, 15);

   return arr;
   delete[] arr;
}

bool checkVowel(char * engStr, int count)
{
   if (
      engStr[count] == 'a' ||
      engStr[count] == 'e' ||
      engStr[count] == 'i' ||
      engStr[count] == 'o' ||
      engStr[count] == 'u'
      )
      return true;
   else
      return false;
}

char * convertToPigLatin(char * engStr, char * pLatinStr)
{
   char * arr = new char[20];
   int count = 0;
   pLatinStr = arr;

   while (engStr[count] != '\0')
   {
      bool vowel = checkVowel(engStr, count);
      if (vowel && count == 0)
      {
         stringCopyVowelFirst(pLatinStr, engStr);
         break;
      }
      else
         if (vowel)
         {
            stringCopyAfterVowel(pLatinStr, engStr, count);
            break;
         }
      count++;
   }

   return pLatinStr;
   delete[] arr;
}

void stringCopyAfterVowel(char *& pLatinStr, char * engStr, int count)
{
   int LtnIndex = 0;
   char ayStr[] = "ay\0";
   char tempStr[20];
   tempStr[0] = 0;

   strcpy_s(pLatinStr, 15, engStr);
   strncat_s(tempStr, strlen(tempStr) + 10, engStr, count);

   while (engStr[count] != '\0')
   {
      pLatinStr[LtnIndex] = engStr[count];
      count++;
      LtnIndex++;
   }

   pLatinStr[LtnIndex] = '-';
   pLatinStr[LtnIndex + 1] = '\0';

   strcat_s(pLatinStr, 15, tempStr);
   strcat_s(pLatinStr, 15, ayStr);
}

void stringCopyVowelFirst(char *& pLatinStr, char * engStr)
{
   char wayStr[] = "-way\0";

   strcpy_s(pLatinStr, 15, engStr);
   strcat_s(pLatinStr, 15, wayStr);
}

void outPutResults(ofstream &outFile, char * engStr, char * pLatinStr)
{
   outFile.open("pigLatinOut.txt", std::ofstream::app);

   outFile << left << setw(12) << engStr << "\t";
   outFile << setw(14) << pLatinStr << endl;

   outFile.close();
}

非常感谢任何帮助。这是关于我学习c ++的第三周。

猪拉丁程序“缓冲太小”错误

0 个答案: