Question

有没有办法让这个查询不那么难看？我想避免代码重复，我不想为这么小的代码创建存储过程或函数

select 
    CB.CompanyName as ClientName,
    Sum30 = (
                select 
                    sum(TotalAmount) as sum30 
                from 
                    InvoiceBrowse 
                where 
                    DATEDIFF(day, CreatedOn, @now) > @days_limit AND 
                    DATEDIFF(day, CreatedOn, @now) <= 30 AND 
                    ClientCompanyName = IB.ClientCompanyName
            ),
    Sum60 = (
                select 
                    sum(TotalAmount) as sum30 
                from 
                    InvoiceBrowse 
                where 
                    DATEDIFF(day, CreatedOn, @now) > @days_limit AND 
                    DATEDIFF(day, CreatedOn, @now) <= 60 AND 
                    ClientCompanyName = IB.ClientCompanyName
            ),
    Sum90 = (
                select 
                    sum(TotalAmount) as sum30 
                from 
                    InvoiceBrowse 
                where 
                    DATEDIFF(day, CreatedOn, @now) > @days_limit AND 
                    DATEDIFF(day, CreatedOn, @now) <= 90 AND 
                    ClientCompanyName = IB.ClientCompanyName
            )
from  
    InvoiceBrowse IB

一些解释：我有发票的表格，想要计算每家公司的发票金额30 \ 60 \ 90天。

Answer 1

看起来你在你的例子中错过了一个表..但是这样的事情可能有效。

SELECT  ClientCompanyName AS ClientName,
        SUM(CASE WHEN DATEDIFF(day,CreatedOn,@now) <= 30 THEN TotalAmount END) AS Sum30,
        SUM(CASE WHEN DATEDIFF(day,CreatedOn,@now) <= 60 THEN TotalAmount END) AS Sum60,
        SUM(CASE WHEN DATEDIFF(day,CreatedOn,@now) <= 90 THEN TotalAmount END) AS Sum90
FROM    InvoiceBrowse
WHERE   CreatedOn < DATEADD(DAY, -@days_limit, @now)
GROUP BY ClientCompanyName

将参数传递给子查询

1 个答案: