Question

我使用ServiceStack来包装一个只返回xml或json（作为字符串）的组件，并且想知道如何在服务代码中区分是否调用第3个方法的toJson（）或toXml（）方法党对象？

IRequest对象公开一个AcceptTypes数组，该数组可能包含＆＃34; application / json＆＃34;或＆＃34; application / xml＆＃34;或＆＃34; text / xml＆＃34;，是否有一种首选方式可以绝对确定他们要求的格式，并根据该决定做出决定？

谢谢你，斯蒂芬

public partial class GenericServices
{
    public object Any(Generic request)
    {
        try
        {
            var response = new GenericResponse();

            var ruleAppRef = new CatalogRuleApplicationReference(Keys.ServiceEndpoint, request.RuleApp);
            using (var session = new RuleSession(ruleApplicationReference: ruleAppRef))
            {
                var entity = session.CreateEntity(request.EntityName, request.Data);
                if (!string.IsNullOrWhiteSpace(request.RulesetName))
                {
                    entity.ExecuteRuleSet(request.RulesetName);
                }
                else
                {
                    session.ApplyRules();
                }

                var reqTypes = Request.AcceptTypes;
                //todo: best way to determine formatter?
                if(reqTypes.Contains("application/json"))
                    response.Result = entity.GetJson();
                if (reqTypes.Contains("application/xml") || reqTypes.Contains("text/xml"))
                    response.Result =  entity.GetXml();
            }
            return response;
        }
        catch (Exception exception)
        {
            _log.Error("GenericServices", exception);
            throw;
        }

    }
}

Answer 1

ServiceStack计算最合适的ResponseType，并在IRequest.ResponseContentType中填充它。

所以你可以用：

来确定它

response.Result = Request.ResponseContentType.MatchesContentType(MimeTypes.Xml)
    ? entity.GetXml()
    : entity.GetJson();

如何在运行时确定ServiceStack请求中的接受类型

1 个答案: