我想通过提取一些函数来重构Promise链。目前我有
<p>所以我想提取I const getData = (uuid) => {
return new Promise((resolve) => {
fetch(
// go fetch stuff
)
.then((response) => {
if (!response.ok) {
return resolve(false);
}
return response;
})
.then(fetchres.json)
.then(response => {
// Do more stuff that requires resolves that I will also want to refactor
})
.catch(err => {
console.log(err);
resolve(false);
});
});
};
不成功响应的部分。但传递任何成功的。我已经把它拉出来了。
resolve现在我可以理解得到错误const resolveUnsuccessfulResponses = (response) => {
if (!response.ok) {
return response.resolve(false);
}
return response;
}
const getData = (uuid) => {
return new Promise((resolve) => {
fetch(
// go fetch stuff
)
.then(resolveUnsuccessfulResponses)
.then(fetchres.json)
.then(response => {
// Do more stuff that requires resolves that I will also want to refactor
})
.catch(err => {
console.log(err);
resolve(false);
});
});
};
。如何在外部函数中解析此Promise？
我应该将resolve is not defined传递给我提取的函数吗？那似乎很笨拙。
resolve我可能最终会有像
这样的东西.then(response => resolveUnsuccessfulResponses(response, resolve))
必须将.then(fetchres.json)
.then(parseResponseData)
.then(postDataSomewhere)
.then(doOtherThings)
.then(doEvenMoreCoolThings)
和response传递给他们每个人似乎都错了
答案 0 :(得分：1)
您应该从外部函数返回一个新的Promise：
const resolveUnsuccessfulResponses = (response) => {
return new Promise((resolve, reject) => {
if (!response.ok) {
return resolve(false);
}
return resolve(response);
});
}