我在Doctrine2中使用Single Table Inheritance来存储多个服务的OAuth凭据。我想使用服务的id作为主键;但是,这并非所有服务都是唯一的。
我已经设置数据库使用鉴别器列和服务的id作为主键,但我找不到让Doctrine使用鉴别器列作为键的方法(除了鉴别器列)。我正在使用docblock注释,如果我将discriminator列添加为@Id字段,我会收到错误:
Duplicate definition of column...in a field or discriminator column mapping.
如果我只将字段定义为鉴别器列,则任何重叠的服务ID都会更新所有匹配的行。
无论如何要做到这一点,除了使用自动生成它的价值?
答案 0 :(得分:2)
您不能,descriminator列不能用作主键的一部分。
为什么这个用例btw需要STI?你必须为你提供的每个open-id服务创建一个新类,听起来很烦人: - )
答案 1 :(得分:2)
对于那些使用Hibernate的人,你可以(至少从JPA 2.1开始)。以下代码perfeclty适用于我的环境(hibernate-entitymanager 4.3.6.Final):
@Entity
@Table(name = "CODIFICATIONS")
@IdClass(CodificationId.class)
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name = Codification.DISCRIMINATOR_COLUMN, discriminatorType = DiscriminatorType.INTEGER)
public abstract class Codification implements Serializable {
public static final String DISCRIMINATOR_COLUMN = "TABLE_ID";
private static final long serialVersionUID = 1L;
@Column(name = "CODIFICATION_ID")
protected Long codificationId;
@Id
@Column(name = DISCRIMINATOR_COLUMN, insertable = false, updatable = false)
protected Long tableId;
@Id
@Column(name = "CODE_ID", insertable = false, updatable = false)
protected Long codeId;
@Column(name = "LONG_NAME")
protected String longName;
@Column(name = "SHORT_NAME")
protected String shortName;
}
public class CodificationId implements Serializable {
private static final long serialVersionUID = 1L;
private Long tableId;
private Long codeId;
public Long getTableId() {
return tableId;
}
public void setTableId(Long tableId) {
this.tableId = tableId;
}
public Long getCodeId() {
return codeId;
}
public void setCodeId(Long codeId) {
this.codeId = codeId;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((tableId == null) ? 0 : tableId.hashCode());
result = prime * result + ((codeId == null) ? 0 : codeId.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
CodificationId other = (CodificationId) obj;
if (tableId == null) {
if (other.tableId != null)
return false;
} else if (!tableId.equals(other.tableId))
return false;
if (codeId == null) {
if (other.codeId != null)
return false;
} else if (!codeId.equals(other.codeId))
return false;
return true;
}
}
@Entity
@DiscriminatorValue(Status.DISCRIMINATOR_VALUE)
public class Status extends Codification {
public static final String DISCRIMINATOR_VALUE = "2";
private static final long serialVersionUID = 1L;
}
然后我使用以下代码配置与Status的关联:
@ManyToOne
@JoinColumnsOrFormulas({
@JoinColumnOrFormula(formula = @JoinFormula(referencedColumnName = Codification.DISCRIMINATOR_COLUMN, value = Status.DISCRIMINATOR_VALUE)),
@JoinColumnOrFormula(column = @JoinColumn(name = "STATUS", referencedColumnName = "CODE_ID")) })
private Status status;