无法使用视图名称" place-info"解析超链接关系的URL。

时间:2016-06-23 17:01:35

标签: django python-2.7 django-rest-framework

我经常搜索这个问题,但没有任何解决方案适合我。我得到无法使用视图名称" place-info"解析超链接关系的URL。您可能未能在API中包含相关模型,或者未能在此字段中错误配置lookup_field属性。当我想通过django中的API访问此资源时。

我收到这样的错误:

Could not resolve URL for hyperlinked relationship using view name "place-info". You may have failed to include the related model in your API, or incorrectly configured the `lookup_field` attribute on this field.

我的模型是屁股:

class TourSite(models.Model):
"""Destination place"""

place_name = models.CharField(max_length=100, blank=False, default='')
place_address = models.CharField(max_length=200, blank=False, default='')
place_image = models.ImageField(upload_to="TourSite", blank=True)

def get_place_name(self):
    return self.place_name

def get_place_address(self):
    return self.place_address

def save(self, *args, **kwargs):
    super(TourSite, self).save(*args, **kwargs)

def __str__(self):
    return self.place_name

class Info(models.Model):
"""Stores information about the place."""
place_name = models.OneToOneField(
        TourSite,
        on_delete = models.CASCADE,
        primary_key = True,
    )

famous_for = models.CharField(max_length=200, blank=True, default='')
brief_info = models.TextField(blank=True, default='')

def get_famous_for(self):
    return self.famous_for

def get_brief_info(self):
    return self.brief_info

def get_place_name(self):
    return self.place_name

def save(self, *args, **kwargs):
    super(Info, self).save(*args, **kwargs)

def __str__(self):
    return "%s is famous for %s"% (self.place_name, self.famous_for)

我的Serailizer:

class InfoSerializer(serializers.ModelSerializer):

class Meta:
    model = Info
    fields = '__all__'

class TourSiteSerializer(serializers.HyperlinkedModelSerializer):
    place_info = serializers.HyperlinkedIdentityField(view_name='place-info')

class Meta:
    model = TourSite
    fields = ('id', 'place_name','place_info', 'place_address', 'place_image')

我的观点:

@api_view(['GET'])
def api_root(request):
return Response({
        'places': reverse('places-list', request=request),
    })


class TourSiteList(DefaultsMixin, generics.ListAPIView):
   queryset = TourSite.objects.all()
   search_fields = ("place_name", "place_address", )
   serializer_class = TourSiteSerializer



class TourSiteDetail(DefaultsMixin, generics.RetrieveUpdateDestroyAPIView):
queryset = TourSite.objects.all()
serializer_class = TourSiteSerializer


class Info(generics.ListAPIView):
queryset = Info.objects.all()
serializer_class = InfoSerializer

我的网址

urlpatterns = [
url(r'^$', views.api_root),

url(r'^places/$', views.TourSiteList.as_view(), name="places-list"),
url(r'^places/(?P<pk>[0-9]+)/$', views.TourSiteDetail.as_view(), name="places-detail"),

url(r'^info/$', views.Info.as_view(), name='place-info'),
]

如何解决此问题?

2 个答案:

答案 0 :(得分:0)

因为我无法发表评论:

您的class Meta班级有错误的缩进。它们应该缩进其适当的类中。如果它只是一个转录错误,那么应该修复这个问题。

答案 1 :(得分:0)

我在[{1}}上遇到类似 if(selectedValue.getSelectedIndex() == 0) { displayRecords.setText("You have selected index 0"); for(int i=0; i<vList.size(); i++) { String tokenizerValue = vList.get(i).toString(); System.out.println(tokenizerValue); textArea.setText(tokenizerValue); } } 的情况,这是模型的主键。

结束时需要为HyperlinkedRelatedField指定OneToOneFieldlookup_field个参数。

以下是此解决方案应用于序列化程序的内容:

lookup_url_kwarg