Question

我有桌子和桌面顾客＆＃39;在这个表格中有许多标题为“Name1＆＃39; ＆＃39; Name2＆＃39;＆＃39; Name3＆＃39; ....＆＃39; Name40＆＃39;其中一些字段只有字母＆＃39; x＆＃39;我想知道有多少＆＃39; x＆＃39;在所有40个领域都有

Answer 1

一种可能的解决方案是：

SELECT 
CASE WHEN [Name] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name1] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name2] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name3] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name4] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name5] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name6] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name7] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name8] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name9] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name10] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name11] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name12] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name13] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name14] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name15] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name16] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name17] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name18] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name19] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name20] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name21] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name22] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name23] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name24] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name25] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name26] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name27] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name28] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name29] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name30] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name31] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name32] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name33] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name34] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name35] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name36] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name37] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name38] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name39] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name40] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name41] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name42] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name43] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name44] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name45] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name46] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name47] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name48] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name49] = 'x' THEN 1 ELSE 0 END +
CASE WHEN [Name50] = 'x' THEN 1 ELSE 0 END
FROM [TableCustomers]

我使用名为Nimble Text（http://nimbletext.com/）的应用程序生成了它，但是如果表的列发生更改，您可以使用动态SQL和sys.columns视图在SQL Server中生成此语句。如果您想要一个这样的例子，请告诉我......

Answer 2

您可以尝试这样的事情：

    select len(name00 + name01 + .. + name40) - len(replace(name00 + name01 + .. + name40, 'x', '')) 
from yourTable;

如何在SQL中的多个字段中计算单个字符

2 个答案: