Question

我正在创建以下SQL表

$options = array(
'uri' => 'http://aahshhs.com',   //wath do this line?????
'location' => 'http://localhost/exer/Server.php',);

获取包含行数和金额的两列表格。

现在我想要的只是最后一行正下方一行中SELECT Nr, nu_betrag_wert AS Amount FROM (SELECT DISTINCT processid, nu_betrag_wert, Nr FROM NU_WERTE WHERE Nr <> '(Nr)' AND nu_betrag_wert is NOT NULL) AS nu_betrag列的总和。

我尝试了类似这样的事情，但没有成功：

Amount

有人可以帮我吗？

Answer 1

我已经成功地在两个SELECT中使用UNION来生成我认为你要求的东西 - 它显示了值列表和底部单独行中的最终求和。

也许是这样的：

CREATE TABLE #nu_werte ( processid INT IDENTITY, nu_betrag_wert int, nr VARCHAR(10) )

INSERT INTO #nu_werte ( nr, nu_betrag_wert )
SELECT 'Gut', 1 UNION
SELECT '(Nr)', 3 UNION
SELECT 'Gut', 5 UNION
SELECT 'Tag', 6 UNION
SELECT 'Tag', 8

WITH nu_betrag ( processid, nu_betrag_wert, nr )
AS
(
  SELECT
    processid,
    nu_betrag_wert,
    nr
  FROM
    #nu_werte
  WHERE
    nr != '(Nr)' AND
    nu_betrag_wert IS NOT NULL
)

SELECT nr, nu_betrag_wert AS amount
FROM
  nu_betrag
UNION
SELECT
  NULL, SUM(nu_betrag_wert) AS amount
FROM
  nu_betrag

Answer 2

刚检查过：

;WITH NU_WERTE AS (
SELECT DISTINCT *
FROM (VALUES
(1,10,'(N0)'),(2,20,'(N0)'),(3,30,'(N0)'),(4,40,'(N0)'),(5,60,'(N0)'),
(6,11,'(N1)'),(7,22,'(N1)'),(8,33,'(N1)'),(9,44,'(N1)'),(10,NULL,'(N1)'),
(11,NULL,'(N1)'),(12,20,'(Nr)'),(13,10,'(Nr)')
) as t (processid, nu_betrag_wert, Nr)
)

SELECT Nr, nu_betrag_wert AS Amount
FROM 
    (SELECT DISTINCT 
         processid, nu_betrag_wert, Nr
     FROM NU_WERTE 
     WHERE Nr <> '(Nr)' AND nu_betrag_wert is NOT NULL) AS nu_betrag
UNION ALL
SELECT  
    Nr, SUM(nu_betrag_wert) AS Zahlbetrag
FROM 
    (SELECT DISTINCT 
         processid, nu_betrag_wert, Nr
     FROM NU_WERTE 
     WHERE Nr <> '(Nr)' AND nu_betrag_wert is NOT NULL) AS nu_betrag
GROUP BY 
    Nr WITH ROLLUP

输出：

Nr      Amount
(N0)    10
(N0)    20
(N0)    30
(N0)    40
(N0)    60
(N1)    11
(N1)    22
(N1)    33
(N1)    44
(N0)    160
(N1)    110
NULL    270

SQL Select语句中特定列的总和

2 个答案: