Question

我想有一个连接用户列表，为此选择了对话框。这是我的第一个小python（3.5）脚本。

import sys
import psutil
import locale
import dialog
import pprint

locale.setlocale(locale.LC_ALL, '')
d = dialog.Dialog(dialog="dialog")
choices = []
i = 0;
users = psutil.users()
for user in users:
        item = ('{0}.'.format(i), user.name)
        choices.append(item)
        i += 1
choices.append(('X', "Exit"))
#pprint.pprint(choices)
#OUTPUT: [('0.', 'root'), ('1.', 'root'), ('X', 'Exit')]
#code, tag = d.menu("List", choices)
code, tag = d.menu("List", choices=[('0.', 'root'), ('1.', 'root'), ('X', 'Exit')])

我的问题是，为什么该对话框适用于内联定义的选项但可以不是当我只提供已经定义的列表与内联定义中提供的列表相同时。

child_output.strip()))
dialog.DialogError: dialog-like terminated due to an error: the dialog-like program exited with status 3 (which was passed to it as the DIALOG_ERROR environment variable). Sometimes, the reason is simply that dialog was given a height or width parameter that is too big for the terminal in use. Its output, with leading and trailing whitespace stripped, was:

Error: Expected at least 6 tokens for --menu, have 4.

Answer 1

将它作为变量传递是不够的，例如：

code, tag = d.menu("List", choices)

应明确声明为：

code, tag = d.menu("List", choices=choices)

如何将变量传递给对话框的选择？

1 个答案: