Question

Ajax无法发送文件（jpg-png）。我无法解决问题。

表单代码

<form action="upload.php" method="post" enctype="multipart/form-data">
 <label for="img"> 
  <button id="post-img">update</button>
  <!-- input hidden !! -->
  <input type="file" name="img" id="a-img" style="visibility:hidden">
</label>

AJAX：

$('#a-img').change(function(){
  var photo = $('form').serialize();
  $.ajax({
    url:'upload.php',
    data: photo,
    success:function(data){
        alert(data);
    }
   });
});

php代码：

if($_FILES){
 echo "file ok";
}else{
 echo "no file"; 
}

回调：“没有文件”;

Answer 1

将id frm_send_img添加到表单。

<form action="upload.php" id="frm_send_img" method="post" enctype="multipart/form-data">
 <label for="img"> 
  <button id="post-img">update</button>
  <!-- input hidden !! -->
  <input type="file" name="img" id="a-img" style="visibility:hidden">
</label>

更改下面的脚本。

 $('#a-img').change(function(){
            var photo = new FormData($("#frm_send_img")[0]);

            $.ajax({
                url: "upload.php",
                type: "POST",
                data: photo,
                async: false,
                success: function (msg) {
                    alert(msg)
                },
                cache: false,
                contentType: false,
                processData: false
            });

            e.preventDefault();
        });

Answer 2

你可以这样做：

 $('#a-img').change(function(){
        var frmData = new FormData();
        frmData.append('file', $('#a-img')[0].files[0]);
        $.ajax({
            method: "POST",
            url: "upload.php",
            data: frmData,
        }).done(function (msg) {
          //logic after success
        });

您可以照常访问服务器上的图像：

if (isset($_FILES["img"]["name"]) && $_FILES["img"]["name"] != "") {
     echo "image validation and uploading";
    }else{
     echo "no file uploaded"; 
    }

更改文件（图像）输入ajax无法发布文件

2 个答案: