Question

你好，因为标题建议我需要总结分段数据---＆gt;

can.id       status            qid    marks
001    section 1 question 1    112     3
001    section 1 question 2    117     3
001    section 1 question 3    116     3
001    section 2 question 1    115     3
001    section 2 question 2    114    -1
001    section 2 question 3    111     3
001    section 3 question 1    112    -1
001    section 3 question 2    116     3
002    section 1 question 1    114     3
002    section 1 question 2    111     3
002    section 2 question 2    111    -1
002    section 3 question 1    111    -1

我想为每个部分显示每个can.id的标记总和，感谢帮助....

Answer 1

在R中，我们可以使用dplyr。我们extract（来自tidyr），子串来自＆＃39; status＆＃39;创建＆＃39;部分＆＃39;然后按＆＃39; can.id＆＃39;分组。和＆＃39;部分＆＃39;，获取＆＃39;标记的sum。

library(dplyr)
library(tidyr)
df1 %>% 
  extract(status, into = "section", "(.*\\d+)\\s+[[:alpha:]].*") %>%
  group_by(can.id, section) %>% 
  summarise(SumMarks = sum(marks))
#  can.id   section SumMarks
#   <int>     <chr>    <int>
#1      1 section 1        9
#2      1 section 2        5
#3      1 section 3        2
#4      2 section 1        6
#5      2 section 2       -1
#6      2 section 3       -1

或使用data.table

library(data.table)
setDT(df1)[,.(SumMarks = sum(marks)), .(can.id, 
                 section = sub("\\s+[[:alpha:]].*", "", status))]

数据

 df1 <- structure(list(can.id = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 
 2L, 2L, 2L), status = c("section 1 question 1", "section 1 question 2", 
 "section 1 question 3", "section 2 question 1", "section 2 question 2", 
 "section 2 question 3", "section 3 question 1", "section 3 question 2", 
 "section 1 question 1", "section 1 question 2", "section 2 question 2", 
 "section 3 question 1"), qid = c(112L, 117L, 116L, 115L, 114L, 
  111L, 112L, 116L, 114L, 111L, 111L, 111L), marks = c(3L, 3L, 
 3L, 3L, -1L, 3L, -1L, 3L, 3L, 3L, -1L, -1L)), .Names = c("can.id", 
 "status", "qid", "marks"), class = "data.frame",
  row.names = c(NA, -12L))

Answer 2

我用一些SQL回答了这个问题。

您似乎遇到的问题是您的部分需要从状态字段中拆分出来，您可以执行以下操作;

SELECT
    [can.id]
    ,SUBSTRING([status],1,8) Section
    ,SUM(marks) Total
FROM samp_data
GROUP BY
    [can.id]
    ,SUBSTRING([status],1,8)

如果您只想要每组的前三名，请查看下面的相关链接

How to select top 3 values from each group in a table with SQL which have duplicates

部分明智地添加数据

2 个答案:

数据