Question

   con.Open();
    //stringquery=("insert into Tbl_EmployeeDetails values='"+txtName.Text+"','"+txtContact.Text+"','"+txtAddress.Text+"','"+txtEmployeeID.Text+"','"+txtJobLocation.Text+"','"+txtDateOfBirth.Text+"','"+Rdllist.selectedItem.Text+"'");
    //sql command cmd=new sqlcommand(query,con);
    //cmd.ExecuteNonquery();
    SqlCommand cmd= new SqlCommand("Insert into Tbl_EmployeeDetails(Name,Address,Contact,Emp_ID,JobLocation,DateOfBirth,Gender)values(@Name,@Address,@Contact,@Emp_ID,@JobLocation,@DateOfBirth,@Gender)",con);
    cmd.Parameters.AddWithValue("@Name", txtName.Text);
    cmd.Parameters.AddWithValue("@Address", txtAddress.Text);
    cmd.Parameters.AddWithValue("@Contact", txtContact.Text);
    cmd.Parameters.AddWithValue("@Employee_ID", txtEmp_ID.Text);
    cmd.Parameters.AddWithValue("@JobLocation", txtJobLocation.Text);
    cmd.Parameters.AddWithValue("@DateOfBirth", txtDateOfBirth.Text);
    cmd.Parameters.AddWithValue("@Gender", Rdllist.SelectedItem.Text);

    cmd.ExecuteNonQuery();
        ScriptManager.RegisterClientScriptBlock(this,this.GetType(),"alertMessage","alert('Record Inserted Successfully')",true);
        txtName.Text= String.Empty;
        txtAddress.Text= String.Empty;
        txtContact.Text= String.Empty;
        txtEmp_ID.Text= String.Empty;
        txtJobLocation.Text= String.Empty;
        txtDateOfBirth.Text= String.Empty;
       // txtGender.Text= String.Empty;

        con.Close();
    }
}

Answer 1

@Employee_ID应与@Emp_ID相同，与查询相同。

例如：

cmd.Parameters.AddWithValue("@Emp_ID", txtEmp_ID.Text);

因此请尝试：

  con.Open();

     SqlCommand cmd= new SqlCommand("Insert into Tbl_EmployeeDetails(Name,Address,Contact,Emp_ID,JobLocation,DateOfBirth,Gender)values(@Name,@Address,@Contact,@Emp_ID,@JobLocation,@DateOfBirth,@Gender)",con);
     cmd.Parameters.AddWithValue("@Name", txtName.Text);
     cmd.Parameters.AddWithValue("@Address", txtAddress.Text);
     cmd.Parameters.AddWithValue("@Contact", txtContact.Text);
      cmd.Parameters.AddWithValue("@Emp_ID", txtEmp_ID.Text);
      cmd.Parameters.AddWithValue("@JobLocation", txtJobLocation.Text);
     cmd.Parameters.AddWithValue("@DateOfBirth", txtDateOfBirth.Text);
     cmd.Parameters.AddWithValue("@Gender", Rdllist.SelectedItem.Text);

       cmd.ExecuteNonQuery();
         ScriptManager.RegisterClientScriptBlock(this,this.GetType(),"alertMessage","alert('Record Inserted Successfully')",true);
    txtName.Text= String.Empty;
    txtAddress.Text= String.Empty;
    txtContact.Text= String.Empty;
    txtEmp_ID.Text= String.Empty;
    txtJobLocation.Text= String.Empty;
    txtDateOfBirth.Text= String.Empty;
   // txtGender.Text= String.Empty;

    con.Close();
     }
   }

Answer 2

或者您可以将您的值更改为：

values(@Name,@Address,@Contact,@Employee_ID,@JobLocation,@DateOfBirth,@Gender)

因为你这样称呼它：

cmd.Parameters.AddWithValue("@Employee_ID", txtEmp_ID.Text);

或

 values(@Name,@Address,@Contact,@Emp_ID,@JobLocation,@DateOfBirth,@Gender)

 cmd.Parameters.AddWithValue("@Emp_ID", txtEmp_ID.Text);

将在cmd.parameters.addwithvalue中使用值中的名称。

谨防AddWithValue的陷阱：http://blogs.msmvps.com/jcoehoorn/blog/2014/05/12/can-we-stop-using-addwithvalue-already/

必须声明标量变量“@Emp_ID”

2 个答案: