Question

我正在尝试与QuickBlox实施私密的1对1聊天，但是在http://quickblox.com/developers/Chat#Create_dialog之后仅按照Quickblox文档显示群聊。当我尝试仅发送单个occupants_ids时，会出现以下错误：

{
"errors": [
"Occupants_ids cannot be less than one."
]
}

我正在使用以下正文创建Dialog API：

{
"type": 3,
"name": "",
"occupant_id": "13822296"
}

我是否需要更新请求正文中的某些密钥？

Answer 1

请检查：Create new 1-1(private) chat dialog

来自documentaton的代码为我工作：

let chatDialog: QBChatDialog = QBChatDialog(dialogID: nil, type: QBChatDialogType.Private)
chatDialog.occupantIDs = [user.ID]

QBRequest.createDialog(chatDialog, successBlock: {(response: QBResponse?, createdDialog: QBChatDialog?) in completion?(response: response, createdDialog: chatDialog)

    print("sucess + \(response)")

}, errorBlock: {(response: QBResponse!) in

    print("response + \(response)")
})

Answer 2

QBChatDialog *chatDialog = [[QBChatDialog alloc] initWithDialogID:null type:QBChatDialogTypePrivate];
chatDialog.occupantIDs = @[@(1530190)];

[QBRequest createDialog:chatDialog successBlock:^(QBResponse *response, QBChatDialog *createdDialog) {

} errorBlock:^(QBResponse *response) {

}];

你可以使用它，你应该提供一个occupantIds。如果有效，请告诉我。

Answer 3

 let user = QBUUser()
        user.id = UInt(arrDoctors[sender.tag].QuickBloxId)!
        user.fullName = arrDoctors[sender.tag].title.capitalizeFirst
        ServicesManager.instance().chatService.createPrivateChatDialog(withOpponent: user) { (response, dialog) in
            let chatvc = CHAT_STORYBOARD.instantiateViewController(withIdentifier: "ChatViewController") as! ChatViewController
            chatvc.dialog = dialog
            self.navigationController?.pushViewController(chatvc, animated: true)
        }

使用Quickblox在私密聊天中创建对话框问题

3 个答案: