我正在进入酒店预订系统,目前我正在尝试选择可用房间(未预订)。
Rooms DB Structure:
ID
ROOM NAME
CAPACITY
HOTEL RESERVATIONS DB STRUCTURE:
ID
CHECK_IN
CHECK_OUT
ROOMS
...
这是我目前的代码:
function searchFreeRooms($data){
$check_in = $data['fields']['check_in'];
$check_out = $data['fields']['check_out'];
$this->db->select("*");
$this->db->from('core_hotel_rooms');
$this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out' ) ");
$query = $this->db->get();
return $query->result();
}
用户可以一次预订多个房间,预留的房间ID存储在&#34; ROOMS&#34;用逗号分隔:2,3,5
在我的前面,不应该显示此列中存在的房间,但我遇到了麻烦,因为只选择了逗号之前的第一个id(房间),例如:2,3,5&gt;只选择了2,我的前面仍然显示3,5。
问题在于:$this->db->where("id NOT IN (select rooms,total_guests from res_hotel where check_in <= '$check_in' AND check_out >= '$check_in' OR check_in <= '$check_out' AND check_out >= '$check_out' OR check_in >= '$check_in' AND check_out <= '$check_out' ) ");
我试过这个:$this->db->where("id NOT IN (1, 2) ");
它完美无缺,但不是第二个查询的上方法。
抱歉我的英文......
非常感谢所有能提供帮助的人!
答案 0 :(得分:5)
最后,在你的帮助下,我已经解决了我的问题!
工作代码:
function searchFreeRooms($data){
$check_in = $data['fields']['check_in'];
$check_out = $data['fields']['check_out'];
$query1 = $this->db->query("select rooms from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out' )");
$query1_result = $query1->result();
$room_id= array();
foreach($query1_result as $row){
$room_id[] = $row->rooms;
}
$room = implode(",",$room_id);
$ids = explode(",", $room);
$this->db->select("*");
$this->db->from('core_hotel_rooms');
$this->db->where_not_in('id', $ids);
$query = $this->db->get();
return $query->result();
}
非常感谢!
答案 1 :(得分:1)
考虑使用括号
$this->db->where("id NOT IN (select rooms,total_guests from res_hotel where (check_in <= '$check_in' AND check_out >= '$check_in') OR (check_in <= '$check_out' AND check_out >= '$check_out') OR (check_in >= '$check_in' AND check_out <= '$check_out' ) ) ");
答案 2 :(得分:0)
以下是您的问题的解决方案。希望这有帮助:
function searchFreeRooms($data){
$check_in = $data['fields']['check_in'];
$check_out = $data['fields']['check_out'];
$query1 = $this->db->query("select rooms from res_hotel where check_in <= '".$check_in."' AND check_out >= '".$check_in."' OR check_in <= '".$check_out."' AND check_out >= '".$check_out."' OR check_in >= '".$check_in."' AND check_out <= '".$check_out."'")->result_array();
$room_id= array();
foreach($query1 as $row){
$room_id[] = $row->rooms;
}
$room = implode(",",$room_id);
$query = $this->db->query("select * from rooms where id not in (".$room.")");
return $query->result();
}
答案 3 :(得分:0)
$result = $this->db->select('room')
->get('your_table');
foreach($result as $item) {
$array[] = $item['id'];
}
$a = implode(',', $array);
$this->where_not_in('id', $a);
做这样的事情。