启动我的应用时,我在logcat中遇到此错误:
处理:pc.dd.fragment_animation,PID:25093 java.lang.RuntimeException:无法启动活动ComponentInfo {pc.dd.fragment_animation / pc.dd.fragment_animation.MainClass}:android.view.InflateException:二进制XML文件行#8:二进制XML文件行#8:错误膨胀类片段
这是我在主要活动中的xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">
<fragment
android:id="@+id/listFragment"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:name="pc.dd.fragment_animation.newFragment"
/>
</LinearLayout>
这是我的自定义适配器中的孩子:
public class myListAdapter extends ArrayAdapter<Integer> {
public myListAdapter(Context context, int resource, Integer[] objects) {
super(context, resource, objects);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View v = convertView;
if (v == null) {
LayoutInflater vi;
vi = LayoutInflater.from(getContext());
v = vi.inflate(R.layout.fragment_listview, null);
}
Integer objects = getItem(position);
if (objects != null) {
ImageView tt1 = (ImageView) v.findViewById(R.id._fragmentImage);
TextView tt2 = (TextView) v.findViewById(R.id._fragmentNickanme);
TextView tt3 = (TextView) v.findViewById(R.id._fragmentDescription);
if (tt1 != null) {
tt1.setImageResource(objects);
}
}
return v;
}}
最后,这是我的片段,我尝试做自定义ListView:
public class newFragment extends Fragment {
Integer[] items = new Integer[]{R.drawable.image1,R.drawable.picture};
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_listview, container, false);
ListView myListView = (ListView)view.findViewById(R.id.listFragment);
myListAdapter adapter =
new myListAdapter(getActivity(), android.R.layout.simple_list_item_1, items);
myListView.setAdapter( adapter);
return view;
}}
注意:R.id.listFragment位于main_activity.xml。 在代码fragment_listview下面:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:layout_width="match_parent"
android:layout_height="match_parent">
<LinearLayout
android:orientation="horizontal"
android:layout_width="match_parent"
android:layout_height="wrap_content">
<de.hdodenhof.circleimageview.CircleImageView
xmlns:app="http://schemas.android.com/apk/res-auto"
android:id="@+id/_fragmentImage"
android:layout_width="70dp"
android:layout_height="70dp"
android:src="@drawable/picture"
app:civ_border_width="2dp"
app:civ_border_color="#efefef"
android:layout_margin="6dp" />
<LinearLayout
android:orientation="vertical"
android:layout_width="match_parent"
android:layout_height="match_parent">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textAppearance="?android:attr/textAppearanceSmall"
android:text="@string/nickname"
android:id="@+id/_fragmentNickanme"
android:textSize="8pt"
android:layout_margin="4dp"
android:layout_gravity="top"
android:textColor="#282828" />
<TextView
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:textAppearance="?android:attr/textAppearanceMedium"
android:text="@string/string_small_text"
android:id="@+id/_fragmentDescription"
android:textSize="6pt"
android:gravity="bottom"
android:layout_margin="4dp" />
</LinearLayout>
</LinearLayout>
答案 0 :(得分:0)
是的,我只是在我的主要课程中这样做:
<li>
并删除 ListView myListView = (ListView)findViewById(R.id.listMainAct);
myListAdapter adapter =
new myListAdapter(this, android.R.layout.simple_list_item_1, items);
myListView.setAdapter( adapter);
类,thx cricket_007 以获取提示:)