通过gradle任务传递grails run-app的命令行参数

Question

我有一个grails 3应用程序，当我通过gradle bootRun任务运行时，我试图将命令行参数传递给我的应用程序。

我想在配置文件中读取运行时操作的参数。根据yml configration here的grails文档，我尝试将以下内容添加到build.gradle文件中

run {
    systemProperties = System.properties
}

当我添加该配置并运行我的任务时，我收到以下错误：

3:11:20 PM: Executing external task 'bootRun -Dcolor=red -Dfruit=apple'...

FAILURE: Build failed with an exception.

* Where:
Build file 'C:\docs\projects\jet\build.gradle' line: 85

* What went wrong:
A problem occurred evaluating root project 'jet'.
> Could not find method run() for arguments [build_6lnm3xriwcnri1zrvfit1niuu$_run_closure8@4446881a] on root project 'jet'.

* Try:
Run with --stacktrace option to get the stack trace. Run with --info or --debug option to get more log output.

BUILD FAILED

Total time: 8.892 secs
Could not find method run() for arguments [build_6lnm3xriwcnri1zrvfit1niuu$_run_closure8@4446881a] on root project 'jet'.
3:11:32 PM: External task execution finished 'bootRun -Dcolor=red -Dfruit=apple'.

如果我在这里遗失了任何内容，或者有更好的方法，请告诉我。

Answer 1

所以我发现问题是什么。

Grails 3.0使用bootRun作为目标，而不是run。更改添加以下代码修复了问题。

bootRun {
    systemProperties = System.properties
}

希望这有助于每个人。