Question

我编写了以下有效的查询，但是有大量重复。我想为所有字段获取一组值。我想获得的值集将是与LAST_UPDATED的最新日期/时间相对应的值。

$optParams = array(
          'dimensions' => 'ga:medium',
          'filters' => 'ga:medium==organic');

        $results = $analytics->data_ga->get(
          'ga:'.$viewid,
          $start,
          $end,
          'ga:sessions',
          $optParams);

        return $results;

表格属性：

SELECT 
nb_policy.LAST_UPDATED
nb_policy.POLICY_ID,
nb_policy.POLICY_NAME,
customer.NAME,
customer.VANTIVE_ID,
customer.SIEBEL_ID,
NBRP.JOB.JOB_ID,
NBRP.JOB.JOB_TYPE,
NBRP.JOB.JOB_STATE,
NBRP.JOB.SCHEDULE_NAME,
NBRP.JOB.SCHEDULE_TYPE,
NBRP.JOB.KBYTES,
NBRP.JOB.BACKUP_TYPE
FROM nb_policy
LEFT JOIN customer 
ON nb_policy.CUSTOMER_ID = customer.CUSTOMER_ID
RIGHT JOIN NBRP.JOB 
ON nb_policy.POLICY_NAME = NBRP.JOB.CLASS_NAME
WHERE customer.ACTIVE = 1 AND (customer.VANTIVE_ID > 0 OR customer.SIEBEL_ID > 0)

在编辑每个vercelli的代码后，我收到错误：SQL错误[1722] [42000]：ORA-01722：无效的数字

以下是vercelli的代码：

customer.NAME - VARCHAR2
customer.VANTIVE_ID - VARCHAR2
customer.SIEBEL_ID - VARCHAR2
customer.ACTIVE - NUMBER
nb_policy.LAST_UPDATED - CHAR
nb_policy.POLICY_ID - CHAR
nb_policy.POLICY_NAME - VARCHAR2
NBRP.JOB.JOB_ID - NUMBER
NBRP.JOB.JOB_TYPE - NUMBER
NBRP.JOB.JOB_STATE - NUMBER
NBRP.JOB.SCHEDULE_NAME - VARCHAR2
NBRP.JOB.SCHEDULE_TYPE - NUMBER
NBRP.JOB.KBYTES - NUMBER
NBRP.JOB.BACKUP_TYPE - NUMBER

Answer 1

尝试此操作，针对要显示最后一个值的列集更改/*list of fields on group*/。

我编写了以下有效的查询，但是有大量重复。我想为所有字段获取一组值。我想获得的值集将是与LAST_UPDATED的最新日期/时间相对应的值。

SELECT * 
FROM   (SELECT nb_policy.last_updated, 
               nb_policy.policy_id, 
               nb_policy.policy_name, 
               customer.name, 
               customer.vantive_id, 
               customer.siebel_id, 
               nbrp.job.job_id, 
               nbrp.job.job_type, 
               nbrp.job.job_state, 
               nbrp.job.schedule_name, 
               nbrp.job.schedule_type, 
               nbrp.job.kbytes, 
               nbrp.job.backup_type, 
               Row_number() 
                 over ( 
                   PARTITION BY nb_policy.last_updated, nb_policy.policy_id, 
                 nb_policy.policy_name, customer.name, customer.vantive_id, 
                 customer.siebel_id, 
                 nbrp.job.job_id, nbrp.job.job_type, nbrp.job.job_state, 
                 nbrp.job.schedule_name, 
                 nbrp.job.schedule_type, nbrp.job.kbytes, nbrp.job.backup_type 
                   ORDER BY nb_policy.last_updated DESC) AS rn 
        FROM   nb_policy 
               left join customer 
                      ON nb_policy.customer_id = customer.customer_id 
               right join nbrp.job 
                       ON nb_policy.policy_name = nbrp.job.class_name 
        WHERE  customer.active = 1 
               AND ( customer.vantive_id > 0 
                      OR customer.siebel_id > 0 )) t 
WHERE  rn = 1

Oracle SQL - 从查询中为多个值选择上次更新的值

1 个答案: