我要做的是循环一个对象,获取每个候选者出现的总时间并将其打印到页面。
我一直在讨厌这个问题。我是javascript的新手,使用对象对我来说是一件非常新鲜事。
感谢您的帮助!
var entry = [
{
candidate : "guy1",
rank : 1,
state : "AK",
vote_count : "2"
},
{
candidate : "guy2",
rank : 1,
state : "MI",
vote_count : "3"
},
{
candidate : "guy3",
rank : 1,
state : "AK",
vote_count : "5"
},
{
candidate : "guy2",
rank : 1,
state : "AL",
vote_count : "4"
},
{
candidate : "guy2",
rank : 1,
state : "FL",
vote_count : "9"
},
{
candidate : "guy1",
rank : 1,
state : "MN",
vote_count : "7"
}
];
for ( var i = 0, l = entry.canidate.length; i < l; i++ ) {
guy1 += entry.canidate[i];
}
console.log(guy1);
答案 0 :(得分:3)
您可以使用候选人作为关键字并计算投票数。
git prune
&#13;
答案 1 :(得分:1)
您可以使用以下候选人的投票总数创建一个新对象:
https://jsfiddle.net/he58xsb8/
var entry = [
{
candidate : "guy1",
rank : 1,
state : "AK",
vote_count : "2"
},
{
candidate : "guy2",
rank : 1,
state : "MI",
vote_count : "3"
},
{
candidate : "guy3",
rank : 1,
state : "AK",
vote_count : "5"
},
{
candidate : "guy2",
rank : 1,
state : "AL",
vote_count : "4"
},
{
candidate : "guy2",
rank : 1,
state : "FL",
vote_count : "9"
},
{
candidate : "guy1",
rank : 1,
state : "MN",
vote_count : "7"
}
];
var voteByCandidate = {};
for ( var i = 0; i < entry.length; i++ ) {
var result = entry[i];
if (!voteByCandidate[result.candidate]) {
voteByCandidate[result.candidate] = 0;
}
voteByCandidate[result.candidate] += result.vote_count * 1; // Convert to number.
}
console.log(voteByCandidate);
答案 2 :(得分:0)
您可以创建候选映射和循环条目数组。对于每个相同的候选者,递增映射中的键。
var candidateMap = {};
entry.forEach( function(candidate) {
candidateMap[candidate.candidate] = candidateMap[candidate.candidate] || 0;
candidateMap[candidate.candidate] += 1;
});
答案 3 :(得分:0)
您可以使用reduce:
轻松完成此操作
var entries = [{ candidate: "guy1", rank: 1, state: "AK", vote_count: "2" }, { candidate: "guy2", rank: 1, state: "MI", vote_count: "3" }, { candidate: "guy3", rank: 1, state: "AK", vote_count: "5" }, { candidate: "guy2", rank: 1, state: "AL", vote_count: "4" }, { candidate: "guy2", rank: 1, state: "FL", vote_count: "9" }, { candidate: "guy1", rank: 1, state: "MN", vote_count: "7" }];
var result = entries.reduce(function(r, c) {
r[c.candidate] = (r[c.candidate] || 0) + parseInt(c.vote_count);
return r;
}, {});
console.log(result);
答案 4 :(得分:0)
我希望得到每个候选人出现的总时间
您可以使用数组filter过滤候选人,然后reduce来计算每个候选人的出现次数
var _filter=[];
entry.filter(function(item){
_filter.push(item.candidate)
})
var _reducedArray =_filter.reduce(function(prev,next){
prev[next] = (prev[next] + 1) || 1;
return prev;
},{});
console.log(_reducedArray);
答案 5 :(得分:0)
这可能就是您所需要的:
const votes = {};
entry.foraEach(item => {
if(!votes.hasOwnProperty(item.candidate)) {
votes[item.candidate] = +item.vote_count;
} else votes[item.candidate] += +item.vote_count;
});
您将拥有votes
对象内的所有候选人和投票。
答案 6 :(得分:-1)
var entry = [
{
candidate : "guy1",
rank : 1,
state : "AK",
vote_count : "2"
},
{
candidate : "guy2",
rank : 1,
state : "MI",
vote_count : "3"
},
{
candidate : "guy3",
rank : 1,
state : "AK",
vote_count : "5"
},
{
candidate : "guy2",
rank : 1,
state : "AL",
vote_count : "4"
},
{
candidate : "guy2",
rank : 1,
state : "FL",
vote_count : "9"
},
{
candidate : "guy1",
rank : 1,
state : "MN",
vote_count : "7"
}
];
function getCandidateTimes(entry, candidateName){
var appearTimes = 0;
for (var i=0, len = entry.length; i < len; i++){
if(entry[i].candidate == candidateName){
appearTimes++;
}
}
return appearTimes;
}
var guy1AppearTimes = getCandidateTimes(entry, 'guy1');
console.log('guy1 appears ' + guy1AppearTimes + ' times!');
var guy2AppearTimes = getCandidateTimes(entry, 'guy2');
console.log('guy2 appears ' + guy2AppearTimes + ' times!');
//and so on.......