Question

我正在尝试获取某人所连接的蒸汽组的ID。这是json输出：

{
    "response": {
        "success": true,
        "groups": [
            {
                "gid": "111"
            },
            {
                "gid": "222"
            },
            {
                "gid": "333"
            },
            {
                "gid": "444"
            },
            {
                "gid": "555"
            }
        ]

    }
}

我是通过以下方式尝试的：

$groupIDs = $reply['response']['groups'];
foreach ($groupIDs as $gID) {
    // Do stuff
}

我收到以下错误，但我很难看到如何纠正错误。

Invalid argument supplied for foreach()

抱歉，我没说清楚。我已经在foreach（）之前解码了它。

    $reply = json_decode($reply, true);

Answer 1

首先，你必须使用php函数json_decode解码json字符串。然后迭代对象，如下所示

$string = '{
    "response": {
        "success": true,
        "groups": [
            {
                "gid": "111"
            },
            {
                "gid": "222"
            },
            {
                "gid": "333"
            },
            {
                "gid": "444"
            },
            {
                "gid": "555"
            }
        ]

    }
}';
$array = json_decode($string);

foreach($array->response->groups as $value ){
    echo $value->gid;
    echo "<br/>";
}

Answer 2

http://php.net/manual/pt_BR/function.json-decode.php

尝试：

$response = json_decode($reply, true);
$groupIDs = $response['response']['groups'];
foreach ($groupIDs as $gID) {
    // Do stuff
}

Answer 3

使用json_decode（$ response）cf doc

$rep = json_decode($response)
foreach ($rep->response->groups as $gID) {
    // Do stuff
}

Answer 4

$groups = $reply['response']->groups;
foreach ($groups as $group) {
    print $group->gid;
}

在json中，每个{}表示被解析为对象，每个[]被解析为数组。

迭代数组（通过json收到）获取值

4 个答案: