我试着这样做
select Barcode from ITList union select Barcode from Equipment_list
intersect select Barcode from Scanneditem
答案 0 :(得分:2)
检查一下:
SELECT a.Barcode FROM Scanneditem AS a
JOIN (SELECT Barcode FROM ITList UNION SELECT Barcode FROM Equipment_list) AS b
ON a.Barcode=b.Barcode;
答案 1 :(得分:1)
您可以使用“存在”
Select * from (select Barcode from ITList union select Barcode from Equipment_list) as t
where exists (select Barcode from Scanneditem where Scanneditem.Barcode = t.Barcode)
答案 2 :(得分:-1)
虽然MySQL中没有INTERSECT运算符,但您可以使用IN子句或EXISTS子句轻松模拟此类查询,具体取决于INTERSECT查询的复杂性。
请试试这个:
SELECT * FROM (SELECT Barcode FROM ITList UNION SELECT Barcode FROM Equipment_list) AS allbarcode
WHERE allbarcode.Barcode IN (SELECT Barcode FROM Scanneditem)
您还可以使用EXISTS子句检查Naveen Goyal sql(下面的回复)。