Question

在我的iPhone应用程序中，我通过传递一些参数来构建URL

，如

C:\Users\nikhil.wagh>npm install -g browser-sync
npm ERR! Windows_NT 6.1.7601
npm ERR! argv "C:\\Program Files\\nodejs\\node.exe" "C:\\Program Files\\nodejs\\
node_modules\\npm\\bin\\npm-cli.js" "install" "-g" "browser-sync"
npm ERR! node v4.4.5
npm ERR! npm  v2.15.5
npm ERR! code ECONNREFUSED
npm ERR! errno ECONNREFUSED
npm ERR! syscall connect

npm ERR! Error: connect ECONNREFUSED 23.235.39.162:443
npm ERR!     at Object.exports._errnoException (util.js:870:11)
npm ERR!     at exports._exceptionWithHostPort (util.js:893:20)
npm ERR!     at TCPConnectWrap.afterConnect [as oncomplete] (net.js:1061:14)
npm ERR!  { [Error: connect ECONNREFUSED 23.235.39.162:443]
npm ERR!   code: 'ECONNREFUSED',
npm ERR!   errno: 'ECONNREFUSED',
npm ERR!   syscall: 'connect',
npm ERR!   address: '23.235.39.162',
npm ERR!   port: 443 }
npm ERR!
npm ERR! If you are behind a proxy, please make sure that the
npm ERR! 'proxy' config is set properly.  See: 'npm help config'

npm ERR! Please include the following file with any support request:
npm ERR!     C:\Users\nikhil.wagh\npm-debug.log

现在我要验证NSURL * url; url = [url URLByAppendingPathComponent:Param1];只接受URL安全字符，其他方法是对我同意的URL进行编码，但我需要验证Param1，因为它暴露给用户进行更改，是有没有任何直接的本地API这样做？，或正则表达式是唯一的方法？请提供正则表达式，如果是这样，Thanx提前

Answer 1

你可以编码

NSString *encodedString = (__bridge_transfer NSString *)
  CFURLCreateStringByAddingPercentEscapes(
    kCFAllocatorDefault,
    (__bridge CFStringRef)originalString,
    NULL,
    CFSTR(":/?#[]@!$&'()*+,;="),
    kCFStringEncodingUTF8);

if (![encodedString isEqualToString:originalString]) {
    // It contains characters that are probably not legal.
}

或者您可以检查上面列出的字符，但那会有什么乐趣？： - ）

NSCharacterSet *charSet = [NSCharacterSet
                             characterSetWithCharactersInString:
                                @":/?#[]@!$&'()*+,;="];
NSRange range = [string rangeOfCharacterFromSet:charSet];

if (range.location != NSNotFound) { ... }

正则表达式，用于验证Objective C中的URL安全字符串

1 个答案: