使行到列进行报告

Question

我有一个简单的数据库（使用MySql），我需要生成一个报告。 我有一个schedule_plan表，由用户提交。

和我的表userinfo包含name，age dll

所以我需要一个报告，它将日期显示为列以及userinfo表中的名称。

Report
+------+--------+--------+--------+-------+
| Name |    1   |    2   |   3    | until day 30/31  |
+------+--------+--------+--------+-------+
| Bob  |     ON |      ON |    ON | ...   |
| Joe  |    OFF |      ON |   OFF | ...   |
| Jim  |     ON |      ON |    ON | ...   |

如果schedule_plan中的absence_code为null，则为ON，如果不为null OFF

Answer 1

create table attendance
(user_id int,attendance_code varchar(1),dte date)
*/
truncate table attendance;
insert into attendance values
(1,'a','2016-01-01'),
(1,null,'2016-01-02'),
(1,'a','2016-01-03'),
(1,'a','2016-01-04'),
(1,'a','2016-01-05'),
(2,'a','2016-01-01'),
(2,'a','2016-01-02'),
(2,null,'2016-01-03'),
(2,null,'2016-01-04'),
(2,'a','2016-01-05')
;
select a.user_id, 
max(case when day(a.dte) = 1 then case when a.attendance_code is not null then 'On' else 'Off' end end) as day1,
max(case when day(a.dte) = 2 then case when a.attendance_code is not null then 'On' else 'Off' end end) as day2,
max(case when day(a.dte) = 3 then case when a.attendance_code is not null then 'On' else 'Off' end end) as day3,
max(case when day(a.dte) = 4 then case when a.attendance_code is not null then 'On' else 'Off' end end) as day4,
max(case when day(a.dte) = 5 then case when a.attendance_code is not null then 'On' else 'Off' end end) as day5
from attendance a
group by a.user_id;