Question

onActivityResult方法返回空白数据，或者从Gallery中选择图像时不会调用。我的实现在API 16,17 ... 22上运行正常，但我遇到了API 23的问题。我读了这篇文章：https://guides.codepath.com/android/Accessing-the-Camera-and-Stored-Media，关于权限。

我的客户已经在运行Android 6的3部手机上测试了该应用并且它们在选择图像时都具有相同的行为。你可以看到一个活动截图，有3个ImageButtons（一个大的，2个小的），当用户点击一个ImageButton时，会触发图库来挑选一个图像，当用户选择一个图像时，ImageButton只是变灰而不是显示挑选的图像。

////onclick method///photo2 is a imagebutton////SELECT_PICTURE2 is the code

photo2_evento.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            Intent intent = new Intent();
            intent.setType("image/*");
            intent.setAction(Intent.ACTION_GET_CONTENT);
            //startActivityForResult(Intent.createChooser(intent, "Escoge
             una imagen"), SELECT_PICTURE2);
            startActivityForResult(intent, SELECT_PICTURE2);

        }
    });

///onactivityResult
    @Override
protected void onActivityResult(int requestCode, int resultCode, Intent
 data) {
           super.onActivityResult(requestCode, resultCode, data);
           if (resultCode == Activity.RESULT_OK) {

              try{

               Uri selectedImageUri = data.getData();        


             if (requestCode == SELECT_PICTURE1) {

                   photo1_path = getRealPathFromURI(selectedImageUri);
                photo1_evento.setImageBitmap(decodeSampledBitmapFromResource(photo1_path, 400, 400));


                }else if(requestCode == SELECT_PICTURE2){

                    photo2_path = getRealPathFromURI(selectedImageUri);
                    photo2_evento.setImageBitmap(decodeSampledBitmapFromResource(photo2_path, 100, 100));


                }else if(requestCode == SELECT_PICTURE3){

                    photo3_path = getRealPathFromURI(selectedImageUri);             

                    photo3_evento.setImageBitmap(decodeSampledBitmapFromResource(photo3_path, 100, 100)); 



                }

              }catch(Exception e){
                  e.printStackTrace();
              }catch (OutOfMemoryError e) {

                  e.printStackTrace();
                  Toast.makeText(getBaseContext(),"memory error", Toast.LENGTH_LONG).show();
              }


                }




}

////decodeSampledBitmapFromResource is just a method provided by Google     Android for sizing images.

////this method is for getting the URI path, I got this code from stackoverflow
public String getRealPathFromURI(Uri contentUri) {


       String[] projection = { MediaStore.Images.Media.DATA };
       Cursor cursor = null;
       try {
           if (Build.VERSION.SDK_INT > 19) {
               // Will return "image:x*"
               String wholeID = DocumentsContract.getDocumentId(contentUri);
               // Split at colon, use second item in the array
               String id = wholeID.split(":")[1];
               // where id is equal to
               String sel = MediaStore.Images.Media._ID + "=?";

               cursor = Publicar_Eventos.this.getContentResolver().query(
                       MediaStore.Images.Media.EXTERNAL_CONTENT_URI,
                       projection, sel, new String[] { id }, null);
           } else {
               cursor = Publicar_Eventos.this.getContentResolver().query(contentUri,
                       projection, null, null, null);
           }
       } catch (Exception e) {
           e.printStackTrace();
       }catch (OutOfMemoryError e) {

           e.printStackTrace();
           Toast.makeText(getBaseContext(),"error de memoria", Toast.LENGTH_LONG).show();
       }

       String path = null;
       try {
           int column_index = cursor.getColumnIndex(MediaStore.Images.Media.DATA);
           cursor.moveToFirst();
           path = cursor.getString(column_index).toString();
           cursor.close();
       } catch (NullPointerException e) {
           e.printStackTrace();
       }
       return path;
   }

onActivityResult不适用于API 23

0 个答案: