Question

我无法获取图片在隐藏的＆＃39;之间来回切换和＆＃39;显示＆＃39;

我正在使用来自的想法 How to create a hidden <img> in JavaScript?

我有两个不同的按钮，使用html尝试一个，另一个使用javascript - 如果我注释掉一行，则显示灯泡照片

 //document.getElementById("light").style.visibility = "hidden";

这行代码在我的＆＃39; init＆＃39;功能

如果我不对该线进行评论，则无论我点击哪个按钮，灯都会保持隐藏状态

我在Safari控制台日志中看不到任何错误

 <!DOCTYPE html>
 <html>
 <body>

 <h1>Switch on the Light</h1>

 <img id="light" src="WebVuCoolOldBulb-2.jpg" style="width:100px" >

 <button type = button

 onclick="document.getElementById('light').src.show ='WebVuCoolOldBulb-2.jpg'"  >Switch On the Light

 </button>
   <input type="button" id="onButton" value="ON" />

 </body>

 <script>

 //document.images['light'].style.visibility = hidden;

  function init() {
     //document.getElementById("light").style.visibility = "hidden";
     var onButton = document.getElementById("onButton");
     onButton.onclick = function() {
        demoVisibility() ;

     }
   }

 function demoVisibility() {
     document.getElementById("light").style.visibility = "show";

 }
  document.addEventListener('readystatechange', function() {
   // Seems like a GOOD PRACTICE - keeps me from getting type error I was getting

     // https://stackoverflow.com/questions/14207922/javascript-error-null-is-not-an-object

     if (document.readyState === "complete") {
       init();
     }
   });



 </script>
 </html>

Answer 1

visibility样式属性的值为visible和hidden。

没有show值。

function init() {
     document.getElementById("light").style.visibility = "hidden";
     var onButton = document.getElementById("onButton");
     onButton.onclick = function() {
        demoVisibility();
     }
   }

 function demoVisibility() {
     document.getElementById("light").style.visibility = "visible";
 }

图像不会在隐藏和显示之间切换

1 个答案: