我必须向<!DOCTYPE html>
<html>
<body>
<img id="myImage" src="Light1.gif" width="500" height ="350">
<p><button onclick="myFunction()">Change Light</button><p>
<p> Click Change Light to change the traffic light. </p>
</body>
</html>提出POST请求，该请求期待以下内容：
ASP WEB APi 2 with OWIN login但是，我总是通过grant_type=password
password=qwerty
username=administrator
responseCode获得FileNotFound异常。我不确定我是否以正确的方式发送400数据。这是我的代码：
POST修改
以下是public JSONObject getLoginToken(String username, String password) {
URL url = null;
HttpURLConnection httpURLConnection = null;
BufferedReader bufferedReader = null;
JSONObject response = null;
try {
url = new URL("someUrl");
httpURLConnection = (HttpURLConnection) url.openConnection();
JSONObject data = new JSONObject();
data.put("username", username);
data.put("password", password);
data.put("grant_type", "password");
httpURLConnection.setChunkedStreamingMode(0);
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
httpURLConnection.setDoInput(true);
OutputStream os = httpURLConnection.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(URLEncoder.encode(data.toString(), "UTF-8"));
writer.flush();
writer.close();
os.close();
httpURLConnection.connect();
bufferedReader = new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream())); // <-- fails here
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = bufferedReader.readLine()) != null) {
sb.append(line + "\n");
}
response = new JSONObject(sb.toString());
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (httpURLConnection != null) {
httpURLConnection.disconnect();
}
}
return response;
}
中端点的创建方式，如果有任何帮助的话。
C#