我有以下代码将GridView
导出到excel文件中。从理论上讲,这段代码应该没有任何麻烦导出。但是,它正在导出空白。
public static void Export(string fileName, GridView gv, System.Web.UI.Control parentControl)
{
HttpContext.Current.Response.Clear();
HttpContext.Current.Response.AddHeader("content-disposition", string.Format("attachment; filename=" + fileName + ".xls"));
HttpContext.Current.Response.ContentType = "application/ms-excel";
using (StringWriter sw = new StringWriter())
{
using (HtmlTextWriter htw = new HtmlTextWriter(sw))
{
// Create a table to contain the grid
Table table = new Table();
// include the gridline settings
table.GridLines = gv.GridLines;
// add the header row to the table
if (gv.HeaderRow != null)
{
GridViewExportUtil.PrepareControlForExport(gv.HeaderRow);
table.Rows.Add(gv.HeaderRow);
}
// add each of the data rows to the table
foreach (GridViewRow row in gv.Rows)
{
GridViewExportUtil.PrepareControlForExport(row);
table.Rows.Add(row);
}
// add the footer row to the table
if (gv.FooterRow != null)
{
GridViewExportUtil.PrepareControlForExport(gv.FooterRow);
table.Rows.Add(gv.FooterRow);
}
//Control 'Content_ctlDisplayIssues_gvIssues' of type 'GridView' must be placed inside a form tag with runat=server.
System.Web.UI.HtmlControls.HtmlForm form = new System.Web.UI.HtmlControls.HtmlForm();
parentControl.Controls.Add(form);
form.Controls.Add(gv);
form.RenderControl(htw);
// render the htmlwriter into the response
HttpContext.Current.Response.Write(sw.ToString());
HttpContext.Current.Response.End();
}
}
}
/// <summary>
/// Replace any of the contained controls with literals
/// </summary>
/// <param name="control"></param>
private static void PrepareControlForExport(Control control)
{
for (int i = 0; i < control.Controls.Count; i++)
{
Control current = control.Controls[i];
if (current is LinkButton)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as LinkButton).Text));
}
else if (current is ImageButton)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as ImageButton).AlternateText));
}
else if (current is HyperLink)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as HyperLink).Text));
}
else if (current is DropDownList)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as DropDownList).SelectedItem.Text));
}
else if (current is CheckBox)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as CheckBox).Checked ? "True" : "False"));
}
else if (current is Image)
{
control.Controls.Remove(current);
control.Controls.AddAt(i, new LiteralControl((current as Image).AlternateText));
}
if (current.HasControls())
{
GridViewExportUtil.PrepareControlForExport(current);
}
}
}
}
我在这里遗漏了什么吗?
答案 0 :(得分:0)
您是否曾在NotePad中打开过Excel文件?它里面没有HTML!然而,您正在使用HtmlTextWriter将数据流式传输到浏览器。我认为这不会起作用。
如果您真的决定将数据转换为Excel原生格式,可以使用Excel interop,也可以寻找更精简的第三方转换工具。
如果您只是需要用户在Excel中打开电子表格,但您并不关心如何将数据传输到浏览器,我建议您使用CSV格式的数据流式传输数据。 this article
答案 1 :(得分:0)
大部分代码都是正确的。这里的问题是HTML Writer没有正确呈现。 John Wu
在他的回答中提到了这一点。所以这里的走动很简单:
而不是;
//Control 'Content_ctlDisplayIssues_gvIssues' of type 'GridView' must be placed inside a form tag with runat=server.
System.Web.UI.HtmlControls.HtmlForm form = new System.Web.UI.HtmlControls.HtmlForm();
parentControl.Controls.Add(form);
form.Controls.Add(gv);
form.RenderControl(htw);
我用过;
//here the table is rendered into the html writer
table.RenderControl(htw);
也很重要,就是在Web.config文件中添加此代码
<add key="PageInspector:ServerCodeMappingSupport" value="Disabled" />
这对我无缝起作用。