Question

我们说我在控制器中了：

$this->set('locations', $this->Location->find('list', array('fields' => array('state')) ));

如何通过选项生成表单选择视图：

<select name="data[Location][state]" class="inputbox" id="Location">
<option value="Arizona">Arizona</option>
<option value="California">California</option>
<option value="Hawaii">Hawaii</option>
</select>

因为它正在生成：

<select name="data[Location][state]" class="inputbox" id="Location">
    <option value="1">Arizona</option>
    <option value="2">California</option>
    <option value="3">Hawaii</option>
    </select>

我知道cakephp默认使用主键作为值，并且有一个已回答的问题，但解决方案对我不起作用： how do you create a select with both value and the label the same from an array in cakephp?

在我看来，我有：

<?php echo $form->select('Location.state', $locations); ?>

我的数据库是：locations
id |状态
1 |亚利桑那
2 |加州
3 |夏威夷
等等

Answer 1

好吧，解决方案很简单......在我的控制器中，fields数组需要指定值和文本：

$this->set('locations', $this->Location->find('list', array('fields' => array('state','state')) ));

Answer 2

调用list时，您可以分别使用keyField和valueField选项配置用于键和值的字段：

http://book.cakephp.org/3.0/en/orm/retrieving-data-and-resultsets.html#finding-key-value-pairs

 <VirtualHost *:80 *:443>
 ServerAdmin myemail@gmail.com

 ServerName www.mysite.com
 ServerAlias www.mysite.com

 Alias /media/ /var/www/mysite/media/
 Alias /static/ /var/www/mysite/static/

 DocumentRoot /var/www/mysite/media/

 <Directory /var/www/mysite>
     Require all granted
 </Directory>

 WSGIDaemonProcess mysite python-path=/var/www/mysiteenv/lib/python2.7/site-packages:/var/www/mysite
 WSGIProcessGroup mysite
 WSGIScriptAlias / /var/www/mysite/wsgi.py/

 # Possible values include: debug, info, notice, warn, error, crit,
 # alert, emerg.
 LogLevel warn

 CustomLog ${APACHE_LOG_DIR}/access.log combined

Answer 3

static inline struct udphdr *udp_hdr(const struct sk_buff *skb)
{
    return (struct udphdr *)skb_transport_header(skb);
}

如何创建表单选择制作值与db数组中的选项文本相同

3 个答案: