Question

每当我尝试运行代码时，总是会显示错误，例如

致命错误：在解包可选值时意外发现nil

firstAddress值为450 Serra Mall, Stanford, CA 94305, United States

继承代码

 @IBAction func locationOneTapped(sender: UIButton) {
        let testURL: NSURL = NSURL(string: "comgooglemaps-x-callback://")!
        if UIApplication.sharedApplication().canOpenURL(testURL) {
            if let address = firstAddress {
                let directionsRequest: String = "comgooglemaps-x-callback://" + "?daddr=\(address)" + "&x-success=sourceapp://?resume=true&x-source=AirApp"
                let directionsURL: NSURL = NSURL(string: directionsRequest)!
                UIApplication.sharedApplication().openURL(directionsURL)
            }

        }
        else {
            NSLog("Can't use comgooglemaps-x-callback:// on this device.")
        }

Answer 1

需要对NSURL的字符串进行编码才能创建有效的NSURL。基于此answer，你应该做类似的事情：

let testURL: NSURL = NSURL(string: "comgooglemaps-x-callback://")!
if UIApplication.sharedApplication().canOpenURL(testURL) {
   if let address = firstAddress?.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet()) {
      let directionsRequest: String = "comgooglemaps-x-callback://" + "?daddr=\(address)" + "&x-success=sourceapp://?resume=true&x-source=AirApp"
      let directionsURL: NSURL = NSURL(string: directionsRequest)!
      UIApplication.sharedApplication().openURL(directionsURL)
   }
}
else {
   NSLog("Can't use comgooglemaps-x-callback:// on this device.")
}

如何正确传递值到谷歌地图网址方案回调？

1 个答案: