Question

给出两个表

USERS
UID NAME
1   KEN

ADRESS
AID UID CITY
1    1  LONDON

我希望有一个Oracle SQL Developer脚本输出两个结果表，就像我已经一个接一个地输入两个select语句一样。

这不起作用，我无法分配u_id变量：

select UID into u_id from USERS where NAME='KEN';
select * from USERS where UID = u_id;
select * from ADRESS where UID = u_id;

输出当然应该是

UID NAME
1   KEN

AID UID CITY
1    1  LONDON

Answer 1

在SQL Developer中至少有两种方法可以做到这一点。

使用绑定变量：

variable u_id number

execute select U_ID into :u_id from USERS where U_NAME='KEN';

select * from USERS where U_ID = :u_id;
select * from ADRESS where U_ID = :u_id;

或使用替换变量：

column U_ID new_value sub_u_id;
set verify off

select U_ID from USERS where U_NAME='KEN';

select * from USERS where U_ID = &sub_u_id;
select * from ADRESS where U_ID = &sub_u_id;

在这种情况下，您可以简化为：

column U_ID new_value sub_u_id;
set verify off

select * from USERS where U_NAME='KEN';
select * from ADRESS where U_ID = &sub_u_id;

详细了解SQL * Plus文档中的variable command，execute command，column command及其new_value clause和substitution variables - 其中大部分内容也适用于SQL Developer。

使用略有不同的列名创建表的演示，以避免键/保留字：

create table USERS (U_ID number, U_NAME varchar2(10));
insert into users values (1, 'KEN');
create table ADRESS(A_ID number, U_ID number, CITY varchar2(10));
insert into adress values (1, 1, 'LONDON');

prompt Demo 1: bind variables

var u_id number
exec select U_ID into :u_id from USERS where U_NAME='KEN';
select * from USERS where U_ID = :u_id;
select * from ADRESS where U_ID = :u_id;

prompt Demo 2: substitution variables

column U_ID new_value sub_u_id;
set verify off
select * from USERS where U_NAME='KEN';
select * from ADRESS where U_ID = &sub_u_id;

作为脚本运行，脚本输出窗口显示：

Table USERS created.

1 row inserted.

Table ADRESS created.

1 row inserted.

Demo 1: bind variables

PL/SQL procedure successfully completed.

      U_ID U_NAME   
---------- ----------
         1 KEN       


      A_ID       U_ID CITY     
---------- ---------- ----------
         1          1 LONDON    

Demo 2: substitution variables

      U_ID U_NAME   
---------- ----------
         1 KEN       

      A_ID       U_ID CITY     
---------- ---------- ----------
         1          1 LONDON

当然，您可以使用PL/SQL procedure successfully completed取消set feedback off消息。

Oracle SQL Developer中的脚本变量

1 个答案: