Question

我创建了一个功能，可以获得具有相同薪水的所有员工名单。但它只会返回第一行但我想要所有数据我该怎么做呢？

功能代码

function getEmployee($employee, $salary) {
  $select = mysql_query("SELECT * FROM $employee where salary = '$$salary'");
  if ($select) {
      while ($row = mysql_fetch_array($select)) {
        $employeeInfo = array(
          'fname' => $row['fname'],
          'mname' => $row['buyQty'],
          'lname' => $row['lname'],
          'employeeCode' => $row['employeeCode'],
          'email' => $row['email'],
          'mobile' => $row['mobile'],
        );
      return $employeeInfo;
    }
  } else {
    echo mysql_error();
  }  
}

函数调用

$entry[] = getEmployee('abc', '10000');
echo "<pre>";
print_r(array_values($entry));
echo "</pre>";

谢谢

Answer 1

尝试

while ($row = mysql_fetch_array($select)) {
        $employeeInfo[] = array(
          'fname' => $row['fname'],
          'mname' => $row['buyQty'],
          'lname' => $row['lname'],
          'employeeCode' => $row['employeeCode'],
          'email' => $row['email'],
          'mobile' => $row['mobile'],
        );
}
return $employeeInfo;

Answer 2

请尝试

function getEmployee($employee, $salary) {
    $select = mysql_query("SELECT * FROM $employee where salary = '$$salary'");
    if ($select) {
      $allEmployeesInfo = array();
      while ($row = mysql_fetch_array($select)) {
        $employeeInfo = array(
        'fname' => $row['fname'],
        'mname' => $row['buyQty'],
        'lname' => $row['lname'],
        'employeeCode' => $row['employeeCode'],
        'email' => $row['email'],
        'mobile' => $row['mobile'],
      );
      array_push($allEmployeesInfo, $employeeInfo);
    }
    return $allEmployeesInfo;
  } else {
    echo mysql_error();
  }  
}

Answer 3

您只获得一个值（迭代中的最后一个数组），因为您实际上会在每次迭代时覆盖$ employeeInfo并且在循环终止时$ employeeInfo仅保留最后一个数组。在getEmployee函数中将其设置为$ employeeInfo []之类的数组。

PHP函数与数组返回类型

3 个答案: