大家早上好,
我需要一些帮助。我有两个需要联合的SQL查询。这是我的第一个询问..(对不起,如果这会很长)
$query1 = new Query();
$query1->params([':category' => $category, ':ownerId' => $ownerId]);
$query1->select('tmp.id, tmp.title , tmp.description, asst.thumbAssetUrl, b1.paramVal as duration, b2.paramVal as clips, asst.fileUrl as video')
->from('listdb.baseData tmp')
->innerJoin(
'listdb.tag tag',
'tag.baseDataId = tmp.id and tag.tag = :category and tag.status = "active"'
)
->innerJoin(
'listdb.baseParam b0',
'b0.baseDataId = tmp.id
and ((b0.paramName = "role"
and (b0.paramValue = "public"))
or ((select count(*) from listdb.baseParam temp
where temp.baseDataId = tmp.id and paramName = "role" )=0))
or (b0.paramName = "role" and b0.paramValue = "public" and tmp.owner = :ownerId)'
)
->leftJoin(
'listdb.baseParam b1',
'b1.baseDataId = tmp.id and b1.paramName="duration" and b1.status = "active"'
)
->leftJoin(
'listdb.baseParam b2',
'b2.baseDataId = tmp.id and b2.paramName="itemCount" and b2.status = "active"'
)
->leftJoin(
'listdb.baseParam b3',
'b3.baseDataId = tmp.id and b3.paramName="previewUrl" and b3.status = "active"'
)
->leftJoin('assetdb.baseData asst', 'asst.id = b3.paramValue and asst.status = "active"')
->where('tmp.status = "active" and tmp.application = "template" and tmp.role = "public"')
->groupBy('tmp.id')
->orderBy(['tmp.upTime' => SORT_DESC]);
我的第二个问题就是这个..
$query2 = new Query();
$query2->params([':category' => $category, ':ownerId' => $ownerId]);
$query2->select('tmp.id, tmp.title , tmp.description, asst.thumbAssetUrl, b1.paramValue as duration, b2.paramValue as clips, asst.fileUrl as video')
->from('listdb.baseData tmp')
->innerJoin(
'listdb.tag tag',
'tag.baseDataId = tmp.id and tag.tag = :category and tag.status = "active"'
)
->innerJoin(
'listdb.baseParam b0',
'b0.baseDataId = tmp.id
and ((b0.paramName = "role"
and (b0.paramValue = "private" or b0.paramValue = "" and b0.paramValue != "public"))
or ((select count(*) from listdb.baseParam temp
where temp.baseDataId = tmp.id and paramName = "role" )=0))
or (b0.paramName = "role" and b0.paramValue = "public" and tmp.owner = :ownerId)'
)
->leftJoin(
'listdb.baseParam b1',
'b1.baseDataId = tmp.id and b1.paramName="duration" and b1.status = "active"'
)
->leftJoin(
'listdb.baseParam b2',
'b2.baseDataId = tmp.id and b2.paramName="item_count" and b2.status = "active"'
)
->leftJoin(
'listdb.base_parambaseParameter b3',
'b3.baseDataId = tmp.id and b3.paramName="previewUrl" and b3.status = "active"'
)
->leftJoin('assetdb.baseData asst', 'asst.id = b3.paramValue and asst.status = "active"')
->innerJoin('listdb.childRestricted cr', 'cr.baseDataId = tmp.id and cr.status = "active" and cr.owner = :ownerId')
->where('tmp.status = "active" and tmp.application = "template" and tmp.role = "private"')
->groupBy('tmp.id')
->orderBy(['tmp.upTime' => SORT_DESC]);
我尝试使用这个联盟
$query = $query2->union($query1, false);
但它似乎没有正确地将两个查询联合起来,因为这会导致结果加倍。这似乎是什么问题。提前谢谢。
答案 0 :(得分:1)
试试这个:
$unionQuery = (new \yii\db\Query())
->from(['dummy_name' => $query1->union($query2)]);
print_r($unionQuery);
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