Question

我能够使用api令牌和下面的命令来接收我需要的json响应。问题是当我尝试过渡到php时。这是工作卷曲示例（显然减去字符串api令牌）。

curl -v -D - -H 'Authorization: Token token="[private_api_token_here]"' -H "Accept: application/json" -H "Content-type: application/json" -X GET -d ' {"status":"collected,pending","transaction_type":"sale,credit","amount_min":"50.00"}' "https://app.mobilecause.com/api/v2/reports/transactions.json?"

这是我最近的PHP尝试。

    $json = '{
              "status": "collected",
              "transaction_type": "sale",
              "amount_min": "50.00"
            }';

        $assoc_array = json_decode($json);
        $urlEncodedString = http_build_query($assoc_array);
        $URL = "https://app.mobilecause.com/api/v2/reports/transactions.json?" . $urlEncodedString;
        $ch = curl_init();
        $header = array();
        $header[] = 'Content-length: 0';
        $header[] = 'Content-type: application/json';
        $header[] = 'Authorization: Bearer [private_api_token_here]';
        curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
        curl_setopt($ch, CURLOPT_URL, $URL);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLINFO_HEADER_OUT, true);
        $info = curl_getinfo($ch);
        $json = json_decode(curl_exec($ch));
        curl_close($ch);
        var_dump($json);

在我看来，我并没有提交正确的标题。我将api令牌保持为一个简单的字符串。在之前的尝试中，我将令牌作为base 64编码提交。另外，我尝试使用以下作为普通字符串和base 64无效：

'Authorization: Token [private_api_token_here]'

和

'Authorization: Token token=[private_api_token_here]'

我很感激任何想法。

Answer 1

请试试这个：

$ch = curl_init();    
curl_setopt($ch, CURLOPT_URL, "https://app.mobilecause.com/api/v2/reports/transactions.json?");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, " {\"status\":\"collected,pending\",\"transaction_type\":\"sale,credit\",\"amount_min\":\"50.00\"}");
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");


$headers = [];
$headers[] = "Authorization: Token token=\"[private_api_token_here]\"";
$headers[] = "Accept: application/json";
$headers[] = "Content-Type: application/json";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}
curl_close ($ch);

var_dump(json_decode( $result ));

curl命令进入php

1 个答案: