我有一个看起来像这样的数组:
Array
(
[0] => Array
(
[0] => Array
(
[product] => 2003
[date] => 2010-09-15 13:27:35
[status] => 3
)
[1] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 1
)
[2] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 6
)
)
[1] => Array
(
[0] => Array
(
[product] => 2003
[date] => 2010-09-12 13:27:35
[status] => 1
)
[1] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 4
)
[2] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 1
)
)
[2] => Array
(
[0] =>
[1] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 1
)
[2] => Array
(
[product] => 2004
[date] => 2010-09-18 13:27:35
[status] => 1
)
)
我想“折叠”每个第二维数组并获取最大DATE值和最大状态值。因此第一个索引将返回2010-09-18 13:27:35和'6'等。
最后一个索引中的空数组使问题更加复杂。我想使用这个空数组并将其报告为MAX日期和状态。
提前感谢!
答案 0 :(得分:1)
感谢您寻找所有人。我想通了。
$date=array();
$status=array();
$availability=array();
foreach($set as $key => $value)
{
foreach($value as $value2)
{
if(isset($value2[1]))
{
$date[$key][]=$value2[1];
$status[$key][]=$value2[2];
}
else
{
$date[$key][]='2022-09-18 13:27:35';
$status[$key][]='0';
}
}
$availability[$key]=array(max($date[$key]),min($status[$key]));
}