Question

有类似的问题，但没有一个能回答我的问题。

我正在使用Swift 2.0我正在开发一个使用CoreLocation显示经度和纬度的项目。

我也使用社交框架发布到Twitter和facebook。

我收到一条错误，上面写着＆＃34;错误：链接器命令失败，退出代码为1＆＃34;然后它告诉我＆＃34;（使用-v查看调用）＆＃34;但我不明白。

我要在这里写一个答案来编写位置服务部分。这是链接https://stackoverflow.com/a/24696878/6140339

这是我的代码：

import UIKit
import Social
import CoreLocation

@UIApplicationMain

class FirstViewController: UIViewController, CLLocationManagerDelegate, UIApplicationDelegate {


var window: UIWindow?
var locationManager: CLLocationManager!
var seenError : Bool = false
var locationFixAchieved: Bool = false
var locationStatus : NSString = "Not Started"

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject : AnyObject]?) -> Bool {
    initLocationManager();
    return true
}

func initLocationManager() {
    seenError = false
    locationFixAchieved = false
    locationManager = CLLocationManager()
    locationManager.delegate = self
    CLLocationManager.locationServicesEnabled()
    locationManager.desiredAccuracy = kCLLocationAccuracyBest

    locationManager.requestAlwaysAuthorization()
}

func locationManager(manager: CLLocationManager, didFailWithError error: NSError) {
    locationManager.stopUpdatingLocation()
    if (error == true) {
        if (seenError == false) {
            seenError = true
            print(error)
        }
    }
}

func locationManager(manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
    if (locationFixAchieved == false) {
        locationFixAchieved = true
        let locationArray = locations as NSArray
        let locationObj = locationArray.lastObject as! CLLocation
        let coord = locationObj.coordinate

        print(coord.latitude)
        print(coord.longitude)
    }
}

func locationManager(manager: CLLocationManager, didChangeAuthorizationStatus status: CLAuthorizationStatus) {
    var shouldIAllow = false

    switch status {
    case CLAuthorizationStatus.Restricted:
        locationStatus = "Restricted Access to location"
    case CLAuthorizationStatus.Denied:
        locationStatus = "User denied access to location"
    case CLAuthorizationStatus.NotDetermined:
        locationStatus = "Status not determined"
    default:
        locationStatus = "Allowed to location Access"
        shouldIAllow = true
    }
    NSNotificationCenter.defaultCenter().postNotificationName("LabelHasBeenUpdated", object: nil)
    if (shouldIAllow == true) {
        NSLog("Location to Allowed")
        //Start location services
        locationManager.startUpdatingLocation()
    } else {
        NSLog("Denied access: \(locationStatus)")
    }
}



@IBAction func postToFacebookButton(sender: UIButton) {
    if(SLComposeViewController.isAvailableForServiceType(SLServiceTypeFacebook)){
        let socialController = SLComposeViewController(forServiceType: SLServiceTypeFacebook)
        //creates post with pre-desired text
        socialController.setInitialText("")

        self.presentViewController(socialController, animated: true, completion: nil)
    }
}


@IBAction func postTweetButton(sender: UIButton) {
    if(SLComposeViewController.isAvailableForServiceType(SLServiceTypeTwitter)){
        let socialController = SLComposeViewController(forServiceType: SLServiceTypeTwitter)
        //creates post with pre-desired text
        socialController.setInitialText("")

        self.presentViewController(socialController, animated: true, completion: nil)
    }
}

override func preferredStatusBarStyle() -> UIStatusBarStyle {
    return .LightContent
}

override func viewDidLoad() {
    super.viewDidLoad()
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

//layer.cornerRadius layer.cornerRadius

}

整条错误消息：

重复符号_main： /Users/user/Library/Developer/Xcode/DerivedData/FarOut-ekrxzlgzfahpruavmlhyhiwiynum/Build/Intermediates/FarOut.build/Debug-iphonesimulator/FarOut.build/Objects-normal/x86_64/AppDelegate.o /Users/user/Library/Developer/Xcode/DerivedData/FarOut-ekrxzlgzfahpruavmlhyhiwiynum/Build/Intermediates/FarOut.build/Debug-iphonesimulator/FarOut.build/Objects-normal/x86_64/FirstViewController.o ld：1个用于体系结构x86_64的重复符号 clang：错误：链接器命令失败，退出代码为1（使用-v查看调用）

Answer 1

您的代码在我的Xcode中运行良好。我认为删除Derived数据后，清理和重建将正常工作。还有一件事，你需要拆分AppDelegate和ViewController的代码，因为它们有自己的角色。

Answer 2

同一错误消息有很多不同的问题。（Linker command failed with exit code 1）

1）如果您在不同的课程中有两个same constants，那么此问题也会发生。

2）如果您在实施文件中意外导入了.m file而不是.h file。

3）如果您导入了同一个库的两个不同版本，也会发生此错误，在这种情况下只需删除旧版本并只保留一个版本。

4）添加＆＃34; other linker flags＆＃34; in＆＃34; Project＆＃34;而不是＆＃34; Targets＆＃34;。因此，您将其移至＆＃34; Targets＆＃34;，它不应该在＆＃34; Project＆＃34;。

5）在项目 - ＆gt; target-＆gt;构建设置 - ＆gt;中查看它在DEBUG中搜索启用bitcode-> gt;设置NO

看看这个..如果可以，那么一旦确实如此。

菜单＆gt;产品＆gt;清洁 ...然后运行项目

希望它可以帮助你.. :)

Swift：错误：链接器命令失败，退出代码为1

2 个答案: