Question

问题：

显示所有员工的last_name，薪水和工作，这些员工的收入超过美国境外每个部门的所有最低薪员工。从此查询中排除总裁和副总裁。（使用子查询/连接）

我不确定如何正确使用子查询来正确构建

这就是我的尝试：

SELECT last_name, salary, job_id
FROM employees join locations
USING(department_id)
WHERE job_id <> ANY (SELECT *  
                    FROM employees
                    WHERE job_id <> 'AD_PRES' OR job_id <> 'AD_VP')
AND salary > 
                    (SELECT MIN(salary)
                    FROM employees
                    WHERE country_id <> 'US');

任何有关如何正确构建此问题的帮助表示赞赏。谢谢。

Answer 1

LAST_NAME                     SALARY JOB_ID   
------------------------- ---------- ----------
Hartstein                      13000 MK_MAN     
Banda                           6200 SA_REP     
Johnson                         6200 SA_REP     
Ande                            6400 SA_REP     
Lee                             6800 SA_REP     
Sewall                          7000 SA_REP     
Tuvault                         7000 SA_REP     
Marvins                         7200 SA_REP     
Bates                           7300 SA_REP     
Smith                           7400 SA_REP     
Cambrault                       7500 SA_REP     
Doran                           7500 SA_REP     
Smith                           8000 SA_REP     
Olsen                           8000 SA_REP     
Livingston                      8400 SA_REP     
Taylor                          8600 SA_REP     
Hutton                          8800 SA_REP     
Hall                            9000 SA_REP     
McEwen                          9000 SA_REP     
Sully                           9500 SA_REP     
Bernstein                       9500 SA_REP     
Greene                          9500 SA_REP     
Fox                             9600 SA_REP     
Bloom                          10000 SA_REP     
Tucker                         10000 SA_REP     
King                           10000 SA_REP     
Zlotkey                        10500 SA_MAN     
Vishney                        10500 SA_REP     
Cambrault                      11000 SA_MAN     
Abel                           11000 SA_REP     
Ozer                           11500 SA_REP     
Errazuriz                      12000 SA_MAN     
Partners                       13500 SA_MAN     
Russell                        14000 SA_MAN

<强>输出：

SELECT last_name,
       salary,
       job_id
FROM   employees e
       INNER JOIN
       departments d
       ON ( d.department_id = e.department_id )
       INNER JOIN
       locations l
       ON ( d.location_id = l.location_id )
WHERE  e.job_id NOT IN ( 'AD_PRES', 'AD_VP' )
AND    l.country_id <> 'US'
AND    e.salary > ANY( SELECT salary
                       FROM   employees ee
                       WHERE  ee.department_id = e.department_id );

查询2 - 不使用分析函数：

AND    e.salary > ( SELECT MIN( salary )
                    FROM   employees ee
                    WHERE  ee.department_id = e.department_id );

或

{{1}}

Answer 2

SELECT
    last_name, salary, job_id
FROM employees a
INNER JOIN locations b ON a.department_id = b.department_id
WHERE a.job_id NOT IN (
    SELECT job_id
    FROM employees
    WHERE 
        ( job_id <> 'AD_PRES' OR job_id <> 'AD_VP' ) AND
        salary > (
            SELECT MIN(salary)
            FROM employees
            WHERE country_id <> 'US'
        )
);

作品？

坚持Oracle输出

2 个答案: