我使用输入和输出参数定义了一个存储过程,当我尝试调用存储过程时出现以下错误。
[SQL0312]变量KUNNR未定义或不可用。
CALL R3QA6DATA.SP_ADDRESS_CHANGES('1999-12-31 23:59:59','2016-06-01 23:59:59',:KUNNR,:KUNN2,:NAME1,:NAME2,:STRAS,: ORT01,:REGIO,:PSTLZ,:LAND1,:TELF1,:TELFX,:DEFPA) GO
CREATE PROCEDURE R3QA6DATA.SP_ADDRESS_CHANGES
(IN STARTDATE TIMESTAMP, IN ENDDATE TIMESTAMP,
OUT KUNNR GRAPHIC(10), OUT KUNN2 GRAPHIC(10), OUT NAME1 GRAPHIC(35), OUT NAME2 GRAPHIC(35), OUT STRAS GRAPHIC(35), OUT ORT01 GRAPHIC(35),
OUT REGIO GRAPHIC(3), OUT PSTLZ GRAPHIC(10), OUT LAND1 GRAPHIC(3), OUT TELF1 GRAPHIC(16), OUT TELFX GRAPHIC(31), OUT DEFPA GRAPHIC(1) )
LANGUAGE SQL
BEGIN
SELECT DISTINCT
knvp.kunnr
, knvp.kunn2
, kna1.name1
, kna1.name2
, kna1.stras
, kna1.ort01
, kna1.regio
, kna1.pstlz
, kna1.land1
, kna1.telf1
, kna1.telfx
, knvp.defpa
INTO KUNNR, KUNN2, NAME1, NAME2, STRAS, ORT01, REGIO, PSTLZ, LAND1, TELF1, TELFX, DEFPA
FROM
R3QA6DATA.KNA1 AS kna1
INNER JOIN
R3QA6DATA.ZMBCM AS zmbcm
ON
kna1.KUNNR = zmbcm.KUNAG
INNER JOIN
R3QA6DATA.KNVV AS knvv
ON
( kna1.KUNNR = knvv.KUNNR )
INNER JOIN
R3QA6DATA.KNVP AS knvp
ON
(
knvv.KUNNR = knvp.KUNNR
AND
knvv.VKORG = knvp.VKORG
AND
knvv.VTWEG = knvp.VTWEG
AND
knvv.SPART = knvp.SPART
)
WHERE
kna1.MANDT = '010'
AND
knvp.PARVW IN ('WE', 'AG')
AND
(
knvv.VKORG = zmbcm.VKORG
AND
knvv.VTWEG = zmbcm.VTWEG
AND
knvv.SPART = zmbcm.SPART
)
AND
kna1.loevm = ' '
AND
knvv.loevm = ' '
AND
knvp.KUNN2 IN
(
SELECT
SUBSTRING(bdcp2.tabkey, 4, 10)
FROM
R3QA6DATA.BDCP2 AS bdcp2
WHERE
bdcp2.mestype = 'DEBMAS'
AND
(
( bdcp2.tabname = 'KNA1'
AND
bdcp2.fldname IN
('NAME1'
, 'NAME2'
, 'STRAS'
, 'ORT01'
, 'REGIO'
, 'LAND1'
, 'PSTLZ'
, 'TELF1'
, 'TELFX') )
OR
( bdcp2.tabname = 'KNVP' )
)
AND
(
bdcp2.cretime > STARTDATE
AND
bdcp2.cretime < ENDDATE
)
)
AND
zmbcm.STOREID = 4 ;
END
Go
答案 0 :(得分:0)
在RPGLE或COBOL中,如果您在外部源中定义了变量并通过COPY语句访问,则通常会发生此问题。如果问题出现这种情况,请尝试通过INCLUDE使用源代码。