Question

这个小测试脚本显示了我的问题。它会发送消息，关闭所有套接字，然后等待，永不退出。假设将ZMQ_LINGER设置为0应该使其立即丢弃所有排队的消息，那么为什么这不允许我的Node.js进程退出？

const zmq = require('zmq')

const bindUrl = 'tcp://127.0.0.1:4000'
let timer

let publisher = zmq.socket('pub')
publisher.monitor(500, 0)
publisher.setsockopt(zmq.ZMQ_LINGER, 0)
publisher.bind(bindUrl)

let subscriber = zmq.socket('sub')
subscriber.monitor(500, 0)
subscriber.setsockopt(zmq.ZMQ_LINGER, 0)
subscriber.connect(bindUrl)

subscriber.on('connect_error', () => {
  console.log('connect error')
})

subscriber.on('connect', () => {
  subscriber.subscribe('some topic')
})

publisher.on('bind', function () {
  console.log('bound')
  timer = setInterval(() => publisher.send(['some topic', 'blah']), 1000)
})

publisher.on('bind_error', function () {
  console.log('bind error')
})

subscriber.on('disconnect', function () {
  console.log('subscriber disconnected')
  subscriber.close()
})

subscriber.on('close', function () {
  console.log('subscriber closed')
  subscriber.removeAllListeners()
  subscriber = null
})

publisher.on('unbind', function () {
  console.log('publisher unbound')
  publisher.close()
})

publisher.on('close', function () {
  console.log('publisher closed')
  publisher.removeAllListeners()
  publisher = null

  subscriber.disconnect(bindUrl)
})

subscriber.on('message', function (topic, message) {
  console.log(topic.toString(), message.toString())
  clearInterval(timer)
  subscriber.unsubscribe('some topic')
  publisher.unbind(bindUrl)
})

输出如下，进程永不退出。

erin@titania:~/$ node test-disconnect.js 
bound
some topic blah
publisher unbound
publisher closed
subscriber disconnected
subscriber closed

Answer 1

我明确监视套接字的原因是导致此行为的原因。当我准备让进程退出时，我必须明确地调用socket.unmonitor。

如何确保ZeroMQ在套接字关闭后不阻止等待消息？

1 个答案: