Question

我正在尝试从C＃执行python脚本。我在以下链接的另一篇文章中找到了实现此目的的方法：run a python script from c#。但是，当进程到达使用(Process process = Process.Start(start))行时，我收到错误。以下是我正在实施的代码：

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;


namespace RunPy
{
    class Program
    {
        static void Main(string[] args)
        {
            // As an example, cmd would be @C:/Python26/python.exe and args would be C://Python26//test.py 100
            String cmd = "@C:/Program Files (x86)/Python27/python.exe";
            String argss = "C:/My_Python_lib/happyBirthday.py 'joe'";
            // Console.Write(argss); this line is just to test the output of the above argss
            // Console.ReadLine(); this line goes with the above line to prevent the window from closing so fast
            run_cmd(cmd, argss);
            //ProcessStartInfo startInfo = new ProcessStartInfo();
            //startInfo.FileName = cmd;
            //Process.Start(cmd);

        }
        private static void run_cmd(string cmd, string args)
        {
            ProcessStartInfo start = new ProcessStartInfo();
            start.FileName = cmd;
            start.Arguments = args;
            start.UseShellExecute = false;
            start.RedirectStandardOutput = true;
            using (Process process = Process.Start(start))
            {
                using (StreamReader reader = process.StandardOutput)
                {
                    string result = reader.ReadToEnd();
                    Console.Write(result);
                }
            }
        }
    }
}

以下是我要回复的错误：

“System.ComponentModel.Win32Exception”类型的未处理异常发生在System.dll
中

任何帮助将不胜感激。谢谢！

Answer 1

您错误地初始化了cmd变量。 “@”应该在引号之前（即@“C：/ ...”）。当然，使用正斜杠而不是反斜杠无论如何都不需要逐字字符串，所以你可以完全省略“@”。

String cmd = "C:/Program Files (x86)/Python27/python.exe";

Answer 2

试试

string cmd = @"C:\Program Files (x86)\Python27\python.exe";

或

string cmd = @"C:\PROGRA~1\Python27\python.exe";

Answer 3

首先读取python exe并将其加载到内存中。

var assembly = Assembly.GetExecutingAssembly();
var resourcePath = assembly.GetManifestResourceNames().Single(str => str.EndsWith("python.exe"));
FileStream outputFileStream = new FileStream(Path.Combine(Directory.GetCurrentDirectory(), resourcePath), FileMode.OpenOrCreate, FileAccess.ReadWrite);
using (Stream stream = assembly.GetManifestResourceStream(resourcePath))
{
    if (stream != null)
    {
        stream.CopyTo(outputFileStream);
        stream.Close();
    }
    outputFileStream.Close();
}

尝试从C＃启动python.exe时出错

3 个答案: