我有以下PHP代码,似乎无法正常工作。我一遍又一遍地看错了,但找不到它们。
<?php
$actkey = rand() . "\n";
$con = mysql_connect("HOST", "USER", "PASS");
if (!$con)
{
die('Unable to connect: ' . mysql_error());
}
mysql_select_db("TABLE", $con);
mysql_query("UPDATE members SET Activation = $actkey WHERE username = 'admin'");
mysql_close($con)
$con2 = mysql_connect("HOST" , "USER" , "PASS");
if (!$con2)
{
die('Unable to connect: ' . mysql_error());
}
mysql_select_db("a1719745_insaneb", $con2);
$query = mysql_query("INSERT INTO Activation (keycode, valid) VALUES ($actkey, 'yes')");
if(!mysql_query($query, $con2)) {
die('Error: ' . mysql_error());
}
mysql_close($con2);
echo "Complete";
?>
有什么想法吗?
答案 0 :(得分:4)
mysql_close($con)
之后缺少分号。