我正在使用IBM MQ Light。
我正在尝试通过java程序在IBM MQ Lite中推送消息,My Connection非常好。当我运行该程序并检查Localhost时,它向我显示客户端已连接但在3-4秒后它将断开连接并在控制台上抛出异常。
以下是我的错误日志:
Problem with subscribe request: amqp:unauthorized-access: AMQXR0042E: A subscribe request was not authorized for channel PlainText received from 127.0.0.1. AMQXR0004E: MQSeries verb=SPISubscribe(String) returned cc=2(int) MQCC_FAILED rc=2035(int) MQRC_NOT_AUTHORIZED
答案 0 :(得分:0)
2035错误代码表示您未获得授权。您可能需要获取更多信息以确定客户端失败的原因。您可以使用MQS_REPORT_NOAUTH或MQSAUTHERRORS设置获取有关授权失败以及失败访问权限的更多信息。
答案 1 :(得分:0)
我有一个示例代码,您可以通过该代码在IBM MQ Lite中推送消息
package com.Queue;
import com.ibm.mqlight.api.ClientOptions;
import com.ibm.mqlight.api.Delivery;
import com.ibm.mqlight.api.DestinationAdapter;
import com.ibm.mqlight.api.NonBlockingClient;
import com.ibm.mqlight.api.NonBlockingClientAdapter;
import com.ibm.mqlight.api.StringDelivery;
public class SendReceive2
{
public static void main(String[] cmdline)
{
ClientOptions clientOpts = ClientOptions.builder().setCredentials("ad", "jms123").build();
NonBlockingClient.create("amqp://localhost", clientOpts, new NonBlockingClientAdapter<Void>()
{
public void onStarted(NonBlockingClient client, Void context)
{
client.subscribe("JmsQueue", new DestinationAdapter<Void>()
{
public void onMessage(NonBlockingClient client, Void context, Delivery delivery)
{
if (delivery.getType() == Delivery.Type.STRING)
System.out.println(((StringDelivery)delivery).getData());
}
}, null, null);
}
}, null);
NonBlockingClient.create("amqp://localhost", clientOpts, new NonBlockingClientAdapter<Void>()
{
public void onStarted(NonBlockingClient client, Void context)
{
client.send("JmsQueue", "Jms Queue is Formed!", null);
}
}, null);
}//main
}//class
试试吧, 它适用于我的情况