Question

我有一个像这样的对象

var Data= {
  "firstname": {
    "excelcolumnName": "firstName",
    "dbcolumn": "one",
    "testinfo": "basictest"
  },
  "labname": {
    "excelcolumnName": "LabName",
    "dbcolumn": "two",
    "testinfo": "basictest"
  },
  "percentCbd": {
    "excelcolumnName": "Percent CBD",
    "dbcolumn": "three",
    "testinfo": "Final Test"
  }

  "percentgeneral": {
    "excelcolumnName": "Percent General",
    "dbcolumn": "four",
    "testinfo": "Final Test"
  }
}

我想过滤并创建包含 testinfo的新对象：＆＃34; basictest＆＃34; 单个对象的输出应该是这样的。

{
"one":"basictest",
"two":"basictest"
}

任何人都可以帮助我。

Answer 1

根据我的理解，您需要一个包含dbcolumn：testinfo mappings

的对象

Check this JSBin

var Data2={};

_.map(Data,(obj)=>{
  if(obj.testinfo==='basictest'){
  var newObj={};
  newObj[obj.dbcolumn]=obj.testinfo;
  return _.assign(Data2,newObj);
  }
});
console.log(Data2);

map函数将每个对象“映射”为其他对象。 assign合并这些键值对。 newObj [obj.dbcolumn]行将'dbcolumn：value'中的值转换为新对象的键。

Answer 2

Var array = [];

for(var i=0;i<Object.keys(Data).length;i++){
  if(data[i].testinfo === 'basictest'){ 
    array.push(data[i]);
  }
}

数组将包含testinfo = 'basictest'

的所有对象

Answer 3

试试这个

const Data = {
  "firstname": {
    "excelcolumnName": "firstName",
    "dbcolumn": "one",
    "testinfo": "basictest"
  },
  "labname": {
    "excelcolumnName": "LabName",
    "dbcolumn": "two",
    "testinfo": "basictest"
  },
  "percentCbd": {
    "excelcolumnName": "Percent CBD",
    "dbcolumn": "three",
    "testinfo": "Final Test"
  },
  "percentgeneral": {
    "excelcolumnName": "Percent General",
    "dbcolumn": "four",
    "testinfo": "Final Test"
  }
}

const result = {} // contain result

for (var i in Data) {
 const item = Data[i]
 result[item.dbcolumn] = item.testinfo // add a new object item
}

console.log(result) // print {one: "basictest", two: "basictest", three: "Final Test", four: "Final Test"}

如何使用javascript或Lodash从多个对象创建单个对象

3 个答案: